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zimovet [89]
3 years ago
11

Please help , this is due today!!

Chemistry
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

1. weak acid

2. weak base

3. weak acid

4. neutral

5. acidic

6. weak base

Explanation:

You can use a pH level scale like the one I attached, to determine each solution.

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Answer:

God's power is not reflected here.

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2 years ago
Express 0.08010 in exponential notation to the proper significant figures
nataly862011 [7]
This would be 8.010 * 10^-2
3 0
4 years ago
The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.
azamat

Answer:

(a) m_{gold}=7.322g

(b)

V_{gold}=0.379cm^3

V_{copper}=0.122cm^3

(c) \rho _{coin}=15.94g/cm^3

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3

m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3}  \\\\V_{copper}=0.122cm^3

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\  \\\rho _{coin}=15.94g/cm^3

Best regards.

3 0
4 years ago
Read 2 more answers
PLEASE HELP I HAVE TO DO THIS BENCHAMRK QUESTION!!!
GuDViN [60]
PLEASE HELP I HAVE TO DO THIS BENCHAMRK QUESTION!!!


The chart shows parts of a plant and an animal, at different levels of organization. Consider the plant images. If we are referring to levels of organization in a plant which picture can BEST be used to fill in box Y?

first picture (A
8 0
3 years ago
Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete
zavuch27 [327]

Answer:

So the volume will be 2.33 L

Explanation:

The reaction for the combustion is:

2 C₄H₁₀ (g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (l)

mass of butane to moles (mass / molar mass)

1.4 g / 58 g/mol

= 0.024 moles

2 moles of butane can produce 8 moles of carbon dioxide

0.024 moles of butane must produce (0.024 × 8) /2

= 0.096 moles of CO₂

Now we apply the Ideal Gases Law to find out the volume formed.

P . V = n . R . T

p = 1atm

n = 0.096 mol

R = 0.082 L.atm/mol.K

T = 273 + 23 = 296K

V = ?

1atm × V = 0.096 mol × 0.082 L.atm/mol.K × 296K

V = 0.096 mol × 0.082 L.atm/mol.K × 296K / 1atm

= 2.33 L

So the volume will be 2.33 L

5 0
3 years ago
Read 2 more answers
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