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I am Lyosha [343]
3 years ago
10

Sodium has an atomic number of 11 and has a net charge of 0. When sodium combines with chlorine, it has a net charge of +1. Why?

A) Sodium loses a negative electron when forming chemical bonds. B) Sodium gains a + proton when forming chemical bonds. C) Sodium loses a + proton when forming chemical bonds. D) Sodium shares a negative electron with chlorine.
Chemistry
2 answers:
Mamont248 [21]3 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

Atomic number of sodium is 11 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{1}.

In order to gain stability, sodium loses one electron and hence it forms a positive ion (Na^{+}).

Thus, we can conclude that when sodium combines with chlorine, it has a net charge of +1 because sodium loses a negative electron when forming chemical bonds.

yKpoI14uk [10]3 years ago
3 0
<span>A)<span>Sodium loses a negative electron when forming chemical bonds</span></span>
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Explanation:

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what is the concentration of a dextrose solution prepared by diluting 14 ml of a 1.0 m dextrose solution to 25 ml using a 25 ml
allsm [11]

The concentration of a dextrose solution prepared by diluting 14 ml of a 1.0 M dextrose solution to 25 ml using a 25 ml volumetric flask is 0.56M.

Concentration is defined as the number of moles of a solute present in the specific volume of a solution.

According to the dilution law, the degree of ionization increases on a dilution and it is inversely proportional to the square root of concentration. The degree of dissociation of an acid is directly proportional to the square root of a volume.

M₁V₁=M₂V₂

Where, M₁=1.0M, V₁=14ml, M₂=?, V₂=25ml

Rearrange the formula for M₂

M₂=(M₁V₁/V₂)

Plug all the values in the formula

M₂=(1.0M×14 ml/25 ml)

M₂=14 M/25

M₂=0.56 M

Therefore, the concentration of a dextrose solution after the dilution is 0.56M.

To know more about dilution

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