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4 years ago

2. Why did Portugal receive Brazil?

Chemistry

1 answer:

Studentka2010 [4]4 years ago

6 0

Answer:

Brazil and Portugal share a privileged relationship,[2] as evidenced in aligned political and diplomatic coordination, as well as economic, social, cultural, legal, technical and scientific cooperation.[3]

According to a 2011 BBC poll, 76% of Portuguese people view Brazil's influence positively, with 8% viewing it negatively, the most favorable perception of Brazil for any other surveyed country in the world.[4]

Explanation:

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what’s the chemical equation for production of potassium vapor and molten sodium chloride from molten potassium chloride and mol

elena-14-01-66 [18.8K]

Answer:

$\huge\boxed{\sf KCl_{(aq)}+Na_{(aq)} \longrightarrow K_{(l)}+NaCl_{(aq)}}$

Explanation:

Chemical formulas for every compound:

Potassium vapor => $K_{(l)$

Molten soldium chloride => $NaCl_{(aq)}$

Molten Potassium chloride => $KCl_{(aq)}$

Molten Sodium Metal => $Na_{(aq)}$

The reaction will be as follows:

$KCl_{(aq)}+Na_{(aq)} \longrightarrow K_{(l)}+NaCl_{(aq)}$

This reaction is usually called displacement reaction in which an element displaces another element of a compund.

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2 years ago

16) Which of the following elements is unique to nucleic acids when studying organic compounds?

FinnZ [79.3K]

The correct answer is: phosphorous

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4 years ago

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How many molecules are in 7V205?

elixir [45]

Answer:

Calculate the number of moles you have by taking the Mass / molar mass. if you have 1000 grams ; then 1,000 g / 151.001 g/mol = X g moles. Then multiply by Avogadros # = 6.022140857 × 10^23 molecules per g mole. The result is the # of molecules of MnSO4

Explanation: Hope this helps

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3 years ago

Find the ph of a 0.250 m solution of nac2h3o2. (the ka value of hc2h3o2 is 1.80×10−5). express your answer numerically to four s

Slav-nsk [51]

Answer is: pH value of solution of NaC₂H₃O₂ is 9.07.
Chemical reaction: C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻.
Ka(HC₂H₃O₂) = 1,8·10⁻⁵.
Ka · Kb = Kw.
1,8·10⁻⁵ mol/dm³ · Kb = 1·10⁻¹⁴ mol²/dm⁶; the ionic product of water at 25°C.
Kb(C₂H₃O₂⁻) = 1·10⁻¹⁴ mol²/dm⁶ ÷ 1,8·10⁻⁵ mol/dm³.
Kb(C₂H₃O₂⁻) = 5,56·10⁻¹⁰ mol/dm³.
c(C₂H₃O₂⁻) = 0,25 M.
[OH⁻] = [HC₂H₃O₂] = x.
[C₂H₃O₂⁻] = 0,25 M - x.
Kb = [OH⁻] · [HC₂H₃O₂] / [C₂H₃O₂⁻].
5,56·10⁻¹⁰ = x² / (0,25 M -x).
Solve quadratic equation: x = [OH⁻] = 0,0000118 M.
pOH = -log[OH⁻] = -log(0,0000118M) = 4,93.
pH + pOH = 14.
pH = 14 - 4,93 = 9,07.

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4 years ago

Complete and balance the following redox equation using the set of smallest whole– number coefficients. Now sum the coefficients

Elena L [17]

Answer : The balanced chemical equation in a acidic solution is,

$BrO_3^-(aq)+6H^+(aq)+3Sb^{3+}(aq)\rightarrow Br^-(aq)+3H_2O(l)+3Sb^{5+}(aq)$

The sum of the coefficients is, 17

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Rules for the balanced chemical equation in acidic solution are :

First we have to write into the two half-reactions.

Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the less number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydrogen ion $(H^+)$ at that side where the less number of hydrogen are present.