Question

A 45ml of a 4M solution of CaBr2 contains how many grams of CaBr2?

Answer 1

The required mass of calcium bromide is 35.98 grams.

What is molarity?

Molarity is any solution is define as the number of moles of solute present in per liter of solution as;

M = n/V, where

• M = molarity = 4M
• V = volume = 45mL = 0.045L

Moles will be calculated by using the above equation as:

n = (4)(0.045) = 0.18 mole

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

• W = given mass
• M = molar mass

Mass of CaBr₂ = (0.18mol)(199.89g/mol) = 35.98g

Hence required mass of CaBr₂ is 35.98 grams.

To know more about molarity, visit the below link:
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