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kow [346]
3 years ago
11

A helium balloon occupies a volume of 1.8 L at 5°C.What volume will it occupy at 85.0°C?​

Chemistry
1 answer:
Zolol [24]3 years ago
5 0
The volume of the balloon at 85.0°C would be 2.3L
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Explanation:

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What is the volume occupied by 4.20 miles of oxygen gas (O2) at STP
Drupady [299]

Answer: 94.13 L

Explanation: In STP in an ideal gas there is a standard value for both temperature and pressure. At STP,pressure is equal to 1atm and the temperature at 0°C is equal to 273.15K. This problem is an ideal gas so we use PV=nRT where R is a constant R= 0.08205 L.atm/mol.K.

To find volume, derive the equation, it becomes V=nRT/P. Substitute the values. V= 4.20 mol( 0.08205L.atm/mol.K)(273.15K) / 1 atm = 94.13 L. The mole units, atm and K will be cancelled out and L will be the remaining unit which is for volume.

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3 years ago
What is the modren system of classificationis based on
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Imagine you needed to identify if an object has undergone a physical change or a chemical change. What information would you nee
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3 years ago
A 40.0-L sample of fluorine is heated from 90.0°C to 186.0°C. What volume will the sample occupy at the higher temperature?
jasenka [17]

Answer:

The volume will be 82.67 L

Explanation:

Charles's Law is the relationship between the volume and temperature of a certain amount of ideal gas. In this way, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T} = k

Having a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

\frac{V1}{T1} =\frac{V2}{T2}

In this case, you know:

  • V1= 40 L
  • T1= 90 °C
  • V2= ?
  • T2= 186 °C

Replacing:

\frac{40L}{90C} =\frac{V2}{186 C}

Solving:

V2=\frac{40L}{90C} *186 C

V2= 82.67 L

<u><em>The volume will be 82.67 L</em></u>

5 0
3 years ago
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