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Nuetrik [128]
3 years ago
7

Calculate the average reaction rate expressed in moles h2 consumed per liter per second

Chemistry
1 answer:
djyliett [7]3 years ago
8 0

Answer:

Average rate of reaction expressed in moles H₂ consumed per liter per second = 0.0025 M/s = 0.0025 mol/L.s

Explanation:

The complete, correct Question, is presented in the attached image to this answer.

The average rate of reaction in terms of the reactant is defined as the total amount of reactant consumed over a period of time divided by total period of time.

Mathematically,

Average rate of reaction = (change in concentration of H₂ over a period of time) ÷ (total period of time)

Average rate of reaction = (-ΔC)/(Δt)

The minus sign is there because the concentration of reactants reduce with time.

change in concentration of H₂ = -ΔC

= -(0.02 - 0.03) = 0.01 M

Time = Δt = 4 - 0 = 4.0 s

Average rate of reaction = (0.01/4) = 0.0025 M/s

We could solve for the average rate of reaction expressed in moles Cl₂ consumed per liter per second

change in concentration of Cl₂ = -ΔC

= -(0.04 - 0.05) = 0.01 M

Time = Δt = 4 - 0 = 4.0 s

Average rate of reaction = (0.01/4) = 0.0025 M/s = 0.0025 mol/L.s

Hope this Helps!!!

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If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount
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<u>Answer:</u> The volume of water required is 398 mL

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

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Oxalic acid is a polyprotic acid. Write balanced chemical equations for the sequence of reactions that oxalic acid can undergo w
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When oxalic acid reacts with water, first, oxalic acid removes one proton and results in the formation of mono acids.

After that, in second step, oxalic acid in aqueous solution removes another proton which shows it is a polyprotic acid.

The chemical equations are: (the reactions occurs in two steps due to presence to hydrogen atoms).

When one proton is removed:

H_{2}C_{2}O_{4} (aq)+H_{2}O (l)\rightarrow HC_{2}O_{4}^{-}(aq)+H_{3}O^{+}(aq)

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The dissociation of oxalic acid in water in shown in the image.






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