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3 years ago

15

Determine the value of K that would make this expression a perfect square

1 answer:

Mumz [18]3 years ago

4 0

Answer: k=9/4

Step-by-step explanation: We can do this by finding a number that adds up to 3 when multiplied by 2. The best way to do this is to use ((b^2)/4) which can usually find you the number for a perfect square based on b, which we have. So, 3^2 / 4 =9/4, meaning k=9/4. We can check:

>x^2 +3x +9/4

> (x+3/2)(x+3/2)

Perfect square.

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A rhombus has its diagonals 7cm and 6 cm whats its area

ipn [44]

$\large\frak{ Given :}$

Diagonal of a rhombus = 7 cm and 6 cm

$\large\frak{Find:}$

Area of a rhombus

$\large\frak{Explanation :}$

$\small\tt Area = \frac{1}{2}× d¹ × d²$

<u>Where,</u>

d¹ = length of diagonal 1
d² = length of diagonal 2

$\implies \small\tt{ \frac{1}{2} \times 7 \times 6}$

$\implies\small\tt{ \frac{1}{2} \times 42 }$

$\implies \small\tt{Area = 21 {cm}^{2} }$

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2 years ago

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valkas [14]

Answer:

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you just need to add 1 to the numerator(number on top) and 8 to the denominator(number at bottom). :)

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RideAnS [48]

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Read 2 more answers