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Rudiy27
2 years ago
7

When a scientist contrasts two or more objects what is he or she looking for?

Physics
2 answers:
tekilochka [14]2 years ago
5 0
When your Contrasting multiple objects, your looking for any differences that may or may not be their. Think Compare and Contrast if that helps, The answer to this is A
brilliants [131]2 years ago
5 0

Answer: a. differences

Explanation:

Making the contrasts means making comparison of the two or more objects on the basis of features they exhibit. A contrast and comparative account will reveal the similarities and differences between the two or more objects. The contrasts can be made on two or more identifiable physical features (such as (size, color, length, height, volume, shape and others) and chemical composition.

A scientist contrasts two or more objects so as to look the differences among them.

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Which of kepler’s laws explains why the sun has a slightly larger angular diameter in january than in july?
Bond [772]

Kepler’s three law is the answer. Kepler’s 3 is the amount of time it takes to orbit the sun is related to size and distance.  Kepler’s 3 is one of the planetary motion and can be stated as all planets move in elliptical orbits, having the sun sits at one of the foci.

7 0
2 years ago
S To minimize neutron leakage from a reactor, the ratio of the surface area to the volume should be a minimum. For a given volum
erastovalidia [21]

To minimize neutron leakage from a reactor, the ratio of the surface area to the volume should be a minimum. For a given volume V the ratio of the sphere will be \frac{4.83598}{c^{\frac{1}{3} } }.

We know that the surface area and volume of the sphere is given by:

A=4 \pi r^{2}\\V=\frac{4}{3} \pi r^{3}

Therefore, the ratio between the surface area and the volume for the sphere will be:

\frac{A}{V}=\frac{4 \pi r^{2}\\}{\frac{4}{3} \pi r^{3}}=\frac{3}{r}

Equating the volume to the constant c, we will find the value of r.

V=c=\frac{4}{3} \pi r^{3}\\r= (\frac{3c}{4\pi} )^{\frac{1}{3} }

Substituting the value of r in the ration between surface area and volume, we get:

\frac{A}{V}=\frac{3}{ (\frac{3c}{4\pi} )^{\frac{1}{3} }}

Calculating the constants, we get:

\frac{4.83598}{c^{\frac{1}{3} } }

Hence, the ration between surface area and volume is \frac{4.83598}{c^{\frac{1}{3} } }

To learn more about surface area and volume of sphere, refer to:

brainly.com/question/4387241

#SPJ4

3 0
1 year ago
Which statement best compares momentum and kinetic energy?
Katyanochek1 [597]
<span>If your options are:

A.Both momentum and kinetic energy are vector quantities. 

B.Momentum is a vector quantity and kinetic energy is a scalar quantity.

C.Kinetic energy is a vector quantity and momentum is a scalar quantity.

D.Both momentum and kinetic energy are scalar quantities.
</span>
The answer on the question given is letter B.<span>Momentum is a vector quantity and kinetic energy is a scalar quantity.</span>
4 0
2 years ago
What are the necessary condition for the production of sound
andre [41]

Explanation:

You need two, maybe three things - something that's vibrating, a medium for those vibrations to propagate in, and a listener to hear it or recording equipment to pick it up

8 0
2 years ago
Read 2 more answers
Points A (-5,6), B (2,-2), and C (-6,-3) are placed in three different quadrants of a Cartesian coordinate system. Convert each
AURORKA [14]

Answer: A (\sqrt{61},309.8°)

              B (2\sqrt{2}, 315°)

             C (3\sqrt{5}, 26.56°)

Explanation: To transform rectangular coordinates into polar coordinates use:

r=\sqrt{x^{2}+y^{2}} and \theta=tan^{-1}(\frac{y}{x})

For point A:

r=\sqrt{(-5)^{2}+6^{2}}

r=\sqrt{61}

\theta=tan^{-1}(\frac{6}{-5})

\theta=tan^{-1}(-1.2)

\theta=-50.2°

Point A is in the II quadrant, so we substract the angle for 360° since it is in degrees:

\theta=360-50.2

\theta= 309.8°

Polar coordinates for point A is (\sqrt{61}, 309.8°)

For point B:

r=\sqrt{2^{2}+(-2)^{2}}

r=\sqrt{8}

r=2\sqrt{2}

\theta=tan^{-1}(\frac{-2}{2} )

\theta=tan^{-1}(1)

\theta=-45°

Point B is in IV quadrant, so:

\theta=360-45

\theta= 315°

Polar coordinates for point B is (2\sqrt{2}, 315°)

For point C:

r=\sqrt{(-6)^{2}+(-3)^{2}}

r=\sqrt{45}

r=3\sqrt{5}

\theta=tan^{-1}(\frac{-3}{-6} )

\theta=tan^{-1}(0.5)

\theta= 26.56°

Polar coordinates for point C is (3\sqrt{5}, 26.56°)

3 0
3 years ago
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