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Rudiy27
3 years ago
7

When a scientist contrasts two or more objects what is he or she looking for?

Physics
2 answers:
tekilochka [14]3 years ago
5 0
When your Contrasting multiple objects, your looking for any differences that may or may not be their. Think Compare and Contrast if that helps, The answer to this is A
brilliants [131]3 years ago
5 0

Answer: a. differences

Explanation:

Making the contrasts means making comparison of the two or more objects on the basis of features they exhibit. A contrast and comparative account will reveal the similarities and differences between the two or more objects. The contrasts can be made on two or more identifiable physical features (such as (size, color, length, height, volume, shape and others) and chemical composition.

A scientist contrasts two or more objects so as to look the differences among them.

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An alternative to CFL bulbs and incandescent bulbs are light-emitting diode (LED) bulbs. A 16-W LED bulb can replace a 100-W inc
Yanka [14]

Answer:

LED bulb = 0.145 A

Incandescent bulb = 0.909 A

CFL bulb = 0.218 A

Explanation:

Given:

Power rating of LED bulb (P₁) = 16 W

Power rating of incandescent bulb (P₂) = 100 W

Power rating of CFL bulb (P₃) = 24 W

Terminal voltage across the circuit (V) = 110 V

We know that, power is related to terminal voltage and current drawn as:

P=VI

Express this in terms of 'I'. This gives,

I=\frac{P}{V}

Now, calculate the current drawn in each bulb using their respective values.

For LED bulb, P_1=16\ W, V=110\ V

So, current drawn is given as:

I_1=\frac{16\ W}{110\ V}=0.145\ A

For incandescent bulb, P_2=100\ W, V=110\ V

So, current drawn is given as:

I_2=\frac{100\ W}{110\ V}=0.909\ A

For CFL bulb, P_3=24\ W, V=110\ V

So, current drawn is given as:

I_3=\frac{24\ W}{110\ V}=0.218\ A

Therefore, the currents drawn through LED bulb, incandescent bulb and CFL bulb are 0.145 A, 0.909 A and 0.218 A respectively.

5 0
3 years ago
A ball is thrown at a 60.0° angle above the horizontal across level ground. It is released from a
yawa3891 [41]
Write out what you have which is:
initial velocity 
final velocity 
Y distance 
degree

You do not have :
a
X distance 
t

from what you have you can plug into your formulas to get time.
6 0
3 years ago
a body of a mass 1kg suspended from a spring is found to stretch the spring by 10cm. (A) what is the spring constant? what is pe
Nikitich [7]

Answer:

(A) The spring constant is <u>98 N/m.</u>

(B) The period of oscillation is <u>0.635 s.</u>

Explanation:

Given:

Mass of the body is, m=1\ kg

Extension length of the spring is, x=10\ cm=0.1\ m

Now, let 'k' be the spring constant.

The force acting on the body is due to gravity only and is equal to its weight.

So, weight of the body is given as:

F_g=mg\\F_g=1\times 9.8\\F_g=9.8\ N

Now, we know that for a spring-mass system, the net force acting on the body is equal to the product of the spring constant and extension length. Therefore,

F_g=kx\\9.8=k(0.1)\\k=\frac{9.8}{0.1}=98\ N/m

Hence, the spring constant is 98 N/m.

(B)

Period of oscillation of a body of spring-mass system in SHM is given as:

T=2\pi\sqrt{\frac{m}{k}}

Plug in the given values and solve for period 'T'. This gives,

T=2\pi\sqrt{\frac{1}{98}}\\T=2\pi\times 0.101\\T=0.635\ s

Therefore, the period of oscillation is 0.635 s.

5 0
3 years ago
A baseball pitcher throws a ball at 97.0 mi/h in the horizontal direction. How far does the ball fall vertically by the time it
mario62 [17]

Answer:

Explanation:

1 mile=5280 ft

1 hour=3600 seconds

Changing speed from mi/h to ft/s

97 mi/h \times \frac {5280}{3600}=142.2666667 ft/s\approx 142.27 ft/s

Time of flight, t=\frac {distance}{speed}=\frac {60.5}{142.27}=0.425257732 s\approx 0.425 s

From fundamental kinematics equations

h=0.5gt^{2} where g is acceleration due to gravity whose value is taken as 32.2 ft/s2 and h is the distance

By substitution

h=0.5\times 32.2\times 0.425^{2}=2.9080625 m\approx 2.91 m

7 0
3 years ago
Someone please help me will give BRAILIEST!!!!!
Alex777 [14]
Uranium is the right answer. Scientists use 5 percent of the uranium after the bomb is refused to create stronger and better nuclear bombs.
6 0
3 years ago
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