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3 years ago

When a scientist contrasts two or more objects what is he or she looking for?

2 answers:

5 0

When your Contrasting multiple objects, your looking for any differences that may or may not be their. Think Compare and Contrast if that helps, The answer to this is A

brilliants [131]3 years ago

5 0

Answer: a. differences

Explanation:

Making the contrasts means making comparison of the two or more objects on the basis of features they exhibit. A contrast and comparative account will reveal the similarities and differences between the two or more objects. The contrasts can be made on two or more identifiable physical features (such as (size, color, length, height, volume, shape and others) and chemical composition.

A scientist contrasts two or more objects so as to look the differences among them.

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A girl walked 200 m from her home to her friend’s home, then she walked 1 km to a shop. She then walked 800 m back to her home.

timama [110]

Answer:

200 meters+1000 meters+800 meters=2000 meters or 2km

Explanation:

1km=1000m

3 0

3 years ago

Freefalling object starts from rest after falling for six seconds what will be its velocity

const2013 [10]

Answer:

60m/s

Explanation:

since the object is falling under the influence of gravity, the formula is

v = u +gt

before the fall, the object is at rest then

u = 0m/s

v = 0 + 10×6 because acceleration due to gravity is g which is given as 10m/s2

therefore, v = 60m/s

7 0

3 years ago

Two magnets are sliding towards each other. One of the magnets, which has a mass of 125 grams, is moving in the positive x-direc

olasank [31]

Answer:

0.45 m/s in the negative x-direction

Explanation:

From the law of conservation of momentum, the sum of initial momentum equals the sum of final momentum

Momentum, p=mv where m is the mass and v is the velocity

$m_1v_1+m_2v_2=(m_1+m_2)v_c$ where $v_c$ is the common velocity, $v_1$ and $v_2$ are velocities of magnet moving in positive x-direction and magnet moving in negative x-direction respectively, $m_1$ and $m_2$ are masses of magnet moving in positive x-direction and magnet moving in negative x-direction respectively.

Substituting 125 g for $m_1$ and 85 g for $m_2$ , 7.33 m/s $v_1$ , -11.9 m/s for $v_1$ then

$125 g\times 7.33 m/s + (85 g\times -11.9)=(125 g+ 85 g)\times v_c$

$-95.25 g. m/s=210 g v_c$

$v_c=\frac {-95.25 g.m/s}{210 g}=-0.453571429 m/s
\approx -0.45 m/s$

Therefore, the velocity of single unit is 0.45 m/s in the negative x-direction

5 0

3 years ago

The metric system is based on units of

Margaret [11]

The metric system is based on units of tens.

7 0

4 years ago

Now suppose you carry out a second Thomson experiment with a different beam that contains two types of particles. In particular,

Tems11 [23]

Answer:

Two off-centered spots in the first phase of the experiment; one centered spot in the second phase of the experiment.

Explanation:

If two particles are selected in which both have the same electron mass and the same velocity, but one of the particles has a charge and the other particle has a charge of 2e. During the first stage of the experiment, the two particles have an electric force equal to F = Eq in the entire vertical direction. The acceleration of particle is equal to a = (Eq)/m.

In the second part of the experiment, the magnetic field cancels the electric field. In this way, the electric force and the magnetic force cancel each other out. Therefore, the net force acting on each particle is equal to zero.

Because these two forces cancel each other out, the particles fail to create two off-center points on the screen in the second part of the experiment. Also, if the loads are different, the deviation is also different. In this way, an off-center point cannot be achieved in the first part of the experiment. There will be two off-center points.

8 0

3 years ago