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s2008m [1.1K]
3 years ago
5

A compound was found to have 85.7% carbon and 14.3% hydrogen. Its molecular mass is 84. What is its empirical formula? What is i

ts molecular formula?
Chemistry
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

The molecular formula is C₆H₁₂

The empirical formula is CH₂

Explanation:

Percent by mass, means that in 100 g of compound we have:

85.7 g of C

14.3 g of H

Let's make a rule of three with the molar mass to determine the amounts of the elements:

In 100 g of compound we have 85.7 g of C

In 84 g of compound we would have (84 . 85.7) / 100 = 72 g of C

In 100 g of compound we have 14.3 g of H

Then, in 84 g of compound we would have (84 . 14.3) / 100 = 12 g of H

Now let's determine the moles of each element

72 g of C / 12 g/mol = 6 mol of C

12 g of H / 1 g/mol = 12 mol of H

Then, the molecular formula is C₆H₁₂

The empirical formula is CH₂

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In fractional distillation, liquid can be seen running from the bottom of the distillation column back into the distilling flask
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Calculate the cell potential at 25oC under the following nonstandard conditions: 2MnO4-(aq) + 3Cu(s) + 8H+(aq) ⟶ 2MnO2(s) + 3Cu2
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1.346 v

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(reduction) MnO_{4 (aq)} + 3e + 4H^{+}_{(aq)}→MnO_{2 (aq)}+2H_{2}O E°=1.679 v

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2) Nernst Equation

Knowing the standard potential, one calculates the nonstandard potential using the Nernst Equation:

E=E^{0} -\frac{RT}{nF}Ln\frac{[red]}{[ox]}

Where 'R' is the molar gas constant, 'T' is the kelvin temperature, 'n' is the number of electrons involved in the reaction and 'F' is the faraday constant.

The problem gives the [red]=0.66M and [ox]=1.69M, just apply to the Nernst Equation to give

E=1.342 -\frac{298.15*8.314}{6*96500}Ln\frac{[.66]}{[1.69]}=1.346

E=1.346

5 0
3 years ago
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