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Illusion [34]
3 years ago
7

In fractional distillation, liquid can be seen running from the bottom of the distillation column back into the distilling flask

. What effect does this returning condensate have on the fractional distillation?
Chemistry
1 answer:
shepuryov [24]3 years ago
7 0

Answer:

substances with a higher boiling point are returning back to the flask which allows another substances with the specific context temperature (lower boiling point) to boil over and be purified.

Explanation:

The reason it happens because the lower boiling point substance vaporizes and crosses over while the other substance is waiting for its boiling point to reach

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A 31.1 g wafer of pure gold, initially at 69.3 _c, is submerged into 64.2 g of water at 27.8 _c in an insulated container. what
KIM [24]
Given:
Ma = 31.1 g, the mass of gold
Ta = 69.3 °C, the initial temperature of gold
Mw = 64.2 g, the mass of water
Tw = 27.8 °C, the initial temperature of water 

Because the container is insulated, no heat is lost to the surroundings.
Let T °C be the final temperature.

From tables, obtain
Ca = 0.129 J/(g-°C), the specific heat of gold
Cw = 4.18 J/(g-°C), the specific heat of water

At equilibrium, heat lost by the gold - heat gained by the water.
Heat lost by the gold is
Qa = Ma*Ca*(T - Ta)
      = (31.1 g)*(0.129 J/(g-°C)(*(69.3 - T °C)- 
      = 4.0119(69.3 - T) j
Heat gained by the water is
Qw = Mw*Cw*(T-Tw)
       = (64.2 g)*(4.18 J/(g-°C))*(T - 27.8 °C)
       = 268.356(T - 27.8)

Equate Qa and Qw.
268.356(T - 27.8) = 4.0119(69.3 - T)
272.3679T = 7738.32
T = 28.41 °C

Answer: 28.4 °C

3 0
3 years ago
Read 2 more answers
Question 10
Rainbow [258]

Answer:

b

Explanation:

jus bc

6 0
3 years ago
Calculate the molarity of the acid solution.<br>H2SO4(aq) with a pH of 2.
Lena [83]

Concentration "molarity" of H₂SO₄ in this solution:

5 × 10⁻³ mol / dm³.

<h3>Explanation</h3>

What's the concentration of H⁺ ions in this solution?

[\text{H}^{+}] = 10^{-\text{pH}},

where [\text{H}^{+}] is in the unit mol / dm³.

\text{pH} = 2

[\text{H}^{+}] = 10^{-2} \;\text{mol}\cdot\text{dm}^{-3}.

What's the concentration "molarity" of H₂SO₄ in this solution?

Sulfuric acid H₂SO₄ is a strong acid. Note the subscript "2". Each mole of this acid dissolves in water to produce two moles of H⁺ ions. It takes only \dfrac{10^{-2}}{2} = 5 \times 10^{-3}\;\text{mol}\cdot\text{dm}^{-3} of H₂SO₄ to produce twice as much H⁺ ions.

As a result, the <em>molarity</em> of H₂SO₄ is 5 × 10⁻³ mol / dm³ or 0.005 M.

3 0
3 years ago
A laser pulse with wavelength 545 nm contains 4.85 mJ of energy. How many photons are in the laser pulse?
dusya [7]

<u>Given</u>:

Wavelength (λ) of the laser pulse = 545 nm = 5.45 * 10⁻⁹ m

Total energy of pulse = 4.85 mJ

<u>To determine:</u>

The number of photons in the laser of a given energy

<u>Explanation:</u>

Energy per photon (E) = hc/λ

where h = planck's constant = 6.626 *10⁻³⁴ Js

C = speed of light = 3*10⁸ m/s

λ = wavelength

E = 6.626 *10⁻³⁴ Js* 3*10⁸ms-1 /5.45 * 10⁻⁹ m = 3.65 * 10⁻¹⁹ J

Now,

# photons = total energy/Energy per photon

                 =  4.85 * 10⁻³ J* 1 photon / 3.65 * 10⁻¹⁹ J = 1.32 * 10¹⁶ photons

Ans: the laser pulse contains 1.32 * 10¹⁶ photons

3 0
3 years ago
What do we call the energy that travels from the sun in the form of waves
Gre4nikov [31]

Answer:

Solar energy is essentially the light and heat emitted from the sun

5 0
3 years ago
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