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Mamont248 [21]
4 years ago
6

A student isolated 25 g of a compound following a procedure that would theoratically yield 81 g. Wht was his percentt yield?

Chemistry
1 answer:
Sati [7]4 years ago
3 0

<u>Answer:</u> The percent yield of the compound is 30.86 %.

<u>Explanation:</u>

To calculate the percentage yield of a compound, we use the equation:

\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield of compound = 25 g

Theoretical yield of compound = 81 g

Putting values in above equation, we get:

\%\text{ yield of compound}=\frac{25g}{81g}\times 100\\\\\% \text{yield of compound}=30.86\%

Hence, the percent yield of the compound is 30.86 %.

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What is the pH at the half-equivalence point in the titration of a weak base with a strong acid? The pKb of the weak base is 7.9
ValentinkaMS [17]

Hey there!

Given the reaction:

B + H⁺   => HB⁺


At half-equivalence point :  [B] = [HB⁺]

=> [B] / [HB⁺] = 1

Henderson-Hasselbalch equation :


pH = pKa + log ( [B] ) / ( HB⁺)]

pH = 14 - pKb + log ( 1 )

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pH = 6.05


Answer C


Hope that helps!



5 0
3 years ago
NH3 + HCI —&gt; NH4CI synthesis O decomposition O single replacement O double replacement​
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Answer:

synthesis

Explanation:

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Given equation:

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The formation of compounds from the union of constituent elements also falls into this category.

So the given reaction is a synthesis reaction.

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In a single replacement reaction, one substance replaces another.

In double replacement reactions partners in a chemical specie are exchanged.

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8 0
3 years ago
How many moles of H2 are needed to react with 4.8 mol of O2 ?
VLD [36.1K]

Answer:

9.6 mol

Explanation:

Start by writing out the balanced equation of the reaction.

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Here you will see 2 mol of hydrogen for every 1 mol of oxygen. Using this ratio, you can assume the amount of hydrogen will always be double that of oxygen. In this case, 4.8 * 2 = 9.6

5 0
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3 years ago
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3 0
3 years ago
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