Answer:
im not sure how to answer this but ...
Explanation:
a jelly bean is not a pure substance it is a mixture.
i hope i helped!!
<h3>
Answer:</h3>
2.6299 g NaCl
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN} FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl
[Given] 2.43306 g FeCl₃
<u>Step 2: Identify Conversions</u>
[RxN] 1 mol FeCl₃ = 3 mol NaCl
Molar Mass of Fe - 55.85 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of Na - 22.99 g/mol
Molar Mass of FeCl₃ = 55.85 + 3(35.45) = 162.2 g/mol
Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We need 5 sig figs (instructed).</em>
2.62986 g NaCl ≈ 2.6299 g NaCl
Answer:
d. 20 protons and 22 neutrons
c. online college and career planning resource you can access once you take the PSAT.
Explanation:
MyRoad is an online platform where college and career planning resources can be accessed when the PSAT has been taken.
It provides an online mentor-ship and guidance for approaching the more robust college life.
The platform allows diverse students to access useful information about their intended colleges.
It also helps in determining career choices and a host of other resources.
Answer:
16.68 m/s
Explanation:
The following data were obtained from the question:
Height (h) = 14.2 m
Initial Velocity (u) = 0 m/s
Final velocity (v) =?
Thus, the velocity (v) with which the ball hit the ground can be obtained as follow:
v² = u² + 2gh
NOTE: the acceleration due to gravity (g) = 9.8 m/s²
v² = u² + 2gh
v² = 0² + 2 × 9.8 × 14.2
v² = 0 + 278.32
v² = 278.32
Take the square root of both side
v = √278.32
v = 16.68 m/s
Therefore, the velocity with which the ball hit the ground is 16.68 m/s