So to solve this question, your goal is to find out how the way it is solved is not correct.
Your answer would be: On the third line, the student adds the 8 to both sides instead of subtracting. The way the initial equation is given is
y-(-8)=-6(x-2). After distributing the six, the student should make the 8 positive because subtracting a negative makes a positive. After solving, the equation should look like: y(+8)=-6x+12, so you would subtract the 8 from both sides instead of adding it, and solve from there.
Answer:
x=3/radical2,-3/radical2,3/4
Step-by-step explanation:
By factoring you get
4x(2x^2-9)-3(2x^2-9)=(2x^2-9)(4x-3)=0
x^2=9/2, x=3/4
x=3radical2/2, -3radical2/2 , 3/4
Answer:
1. a=3
2. a=3
3. a=9
Step-by-step explanation:
1. 9/a+9-4=12-56/8+3
We move all terms to the left:
9/a+9-4-(12-56/8+3)=0
Domain of the equation: a=0
a∈R
We add all the numbers together, and all the variables
9/a+9-4-8=0
We add all the numbers together, and all the variables
9/a-3=0
We multiply all the terms by the denominator
-3*a+9=0
We add all the numbers together, and all the variables
-3a+9=0
We move all terms containing a to the left, all other terms to the right
-3a=-9
a=-9/-3
a=+3
40 goes into 120 3 times, so the answer would be 120 - 40.
Which leaves you with 80 people still at the party.
A would be the answer also if you need anyhelp instantly with math search up wolframalpha just wanted to say
