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Anna11 [10]
3 years ago
12

How many 1/3 cups are in 9 cups?

Mathematics
1 answer:
borishaifa [10]3 years ago
5 0
There are 27 1/3 cups in 9 cups.
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Marizza181 [45]
You can prove it by the SAS postulate which should be the first option
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Can someone help me pls pls help with this question
True [87]

Answer:

D.

Step-by-step explanation:

The mean is 11,000

8 0
3 years ago
Stock worth $80 a share dropped in value by 15% on Tuesday, then increased by $7 the next Wednesday and, finally, increased by 1
Nutka1998 [239]
<h2>Steps</h2>

So here are a couple expressions when a value changes by percentage (p = percentage in decimal form and m = original value):

  • When <em>decrease</em>: (1 - p)m
  • When <em>increase</em>: (1 + p)m

So firstly, the $80 share dropped by 15%. Since this is a <em>decrease</em>, follow the appropriate expression:

15\%=0.15\\\\(1-0.15)*80\\0.85*80\\68

<em>On Tuesday, the share went from $80 to $68</em>

Next, on Wednesday the share increased by $7. With this, just add $68 and 7.

68+7=75

<em>On Wednesday, the share went from $68 to $75</em>

Lastly, on Thursday the share increased by 12%. Since this is an <em>increase</em>, follow the appropriate expression:

12\%=0.12\\\\(1+0.12)*75\\1.12*75\\84

<h2>Answer</h2>

<u>The final price of the share is $84.</u>

7 0
3 years ago
Find the fifth term in the arithmetic sequence that begins at 1.5 and has a common difference of 6.6.
astraxan [27]
I think it's 34.5 (I need more letters so I'm typing this)
4 0
3 years ago
Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence i
mash [69]

Complete Question

A biologist reports a confidence interval of (3.5,4.9) when estimating the mean height (in centimeters) of a sample of seedlings. What is the estimated margin of error and the sample mean?

Answer:

The  margin of error is  E = 0.7

The  sample mean is  \=  x  =  4.2

Step-by-step explanation:

from the question we are told that

   The  upper limit is  k  =  4.9

    The  lower limit is  r = 3.5

Generally the margin of error is mathematically represented as

      E =  \frac{k - r}{ 2}

      E = \frac{ 4.9  -  3.5 }{2}

     E = 0.7

Generally the sample mean is mathematically evaluated as

        \=  x = k  -  E

=>    \= x  =  4.9 - 0.7

=>    \=  x  =  4.2

4 0
3 years ago
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