Answer:
41235
Step-by-step explanation:
There are 120 five-digit numbers that can be made from the digits 1, 2, 3, 4, 5 if each digit is used once in the number,
The total number of times where each number will occur or be at first place is calculated as:
4! = 4 × 3 × 2 × 1
= 24
Hence,
24th number = The last number where 1 is at first place
We can write this out as:
12345
12354
12435
12453
12534
12543
13245
13254
13425
13452
13524
13542 e.t.c.
48th number = The last number where 2 is at first place
72nd place = The last number where 3 is at first place.
This means, the 73rd number is the first number where 4 is at first place.
Therefore, the 73rd number based on pattern is 41235
If Heather puts in 1.36% of her salary into a retirement account and she makes $63,000 in a year, this can be solved by 1.36% x 63000. First convert 1.36% into a decimal. To do this, divide by 100.
1.36/100=0.0136
1.36% x 63000
=0.0136 x 63000
=856.8
Heather would put $856.8 in for the whole year. To find how much per month, divide by 12.
856.8/12=71.<span>4
</span>Rounded to the nearest dollar is $71.
Heather would put $71 into a retirement account each month.
<em>
</em><em>Note: This was solved by multiply the percent and then dividing by 12 months. You could also do this by dividing by 12 months first and then multiplying the percent.</em>
Answer:
Explanation given below.
Step-by-step explanation:
The first step is to put the parabola in the form 
, which is the <em>standard form of a parabola</em>
<em />
<u>Note:</u> a is the coefficient before x^2 term, b is the coefficient before x term, and c is the independent constant term
The axis of symmetry divides the parabola symmetrically. The axis of symmetry has the equation 
Where <em><u>a and b are the respective values shown above</u></em>
<em><u /></em>
So, that is how you get the axis of symmetry of any parabola.
13,61,25,19,41
:) hope i could help :)
Complex zeroes always occurs as conjugates.
For z = a + b i conjugate is: a - b i
Another zero is : 2 + 3 i.
Verification:
2 + 3 i + 3 - 3 i = - b/a
- b = 4, a = 1
( 2 + 3 i ) ( 2 - 3 i ) = c / a
4 - 9 i² = c / a
4 + 9 = c / a
c = 13
( x^4 - 4 x³ + 14 x² - 4 x + 13 ) : ( x² - 4 x + 13 ) = x² + 1
x² + 1 = 0
x² = -1, x = i, x = -i
The zeroes are: - i , i , 2 + 3 i, 2 - 3 i.
Answer:
One another zero of f ( x ) is 2 + 3 i.
