Q1)
molarity is defined as the number of moles of solute in 1 L of solution.
the NaCl solution volume is 1.00 L
number of moles NaCl = NaCl mass present / molar mass of NaCl
NaCl moles = 112 g / 58.5 g/mol = 1.91 mol
the number of moles of NaCl in 1.00 L of solution is - 1.91 mol
therefore molarity of NaCl is 1.91 M
Q2)
molality is defined as the number of moles of solute in 1 kg of solvent.
density is mass per volume.
density of the solution is 1.08 g/mL.
therefore mass of the solution is = density x volume
mass = 1.08 g/mL x 1000 mL = 1080 g
since we have to find the moles in 1 kg of solvent
mass of solvent = 1080 g - 112 g = 968 g
number of moles of NaCl in 968 g of solvent - 1.91 mol
therefore number of NaCl moles in 1000 g - (1.91 mol / 968 g) x 1000 g/kg = 1.97 mol/kg
molality of NaCl solution is 1.97 mol/kg
Q3)
mass percentage is the percentage of mass of solute by total mass of the solution
mass percentage of solution = mass of solute / total mass of the solution
mass of solute = 112 g
total mass of solution = 1080 g
mass % of NaCl = 112 g / 1080 g x 100%
therefore mass % of NaCl = 10.4 %
answer is 10.4 %
Answer:
<h2>
2 is the coefficient of CO₂</h2>
Explanation:
The <u>coefficient</u> is the number in front of a substance that indicates how many molecules or atoms are. For example, when we see 5He, it shows that there are 5 atoms of helium. When we see 5H₂O, it indicates that there are 5 molecules of water, each having 2 atoms of hydrogen and 1 atom of oxygen, so a total of 10 hydrogen atoms and 5 oxygen atoms.
Answer:
Temperate Deciduous Fores
Explanation:
The molar mass of sodium is 22.99 ㅤ ㅤ ㅤ 22.99 (28) = 643.72 mol now multiply by avogrados number to find the number of atoms. ㅤ ㅤ ㅤ 643.72 (6.022 x 10^23) = 3.88 x 10^26 number of atoms
Biomass is organic, meaning it is made of material that comes from living organisms, such as plants and animals. Biomass<span> contains </span>energy<span> first derived from the sun: Plants absorb the sun's </span>energy through<span> photosynthesis.
Answer - photosynthesis</span>