Answer:
1)
Explanation:
the answer to you question Is 1)
One can solve the problem by using the law of conservation of momentum. The total momentum prior to the collision must be equivalent to the total momentum after the collision, so we have:
m1v1 + m2v2 = m1v1 + m2v2
Here, m1 is 0.4 Kg that is the mass of the ball, u1 is 18 m/s that is the initial velocity of the ball, m2 is 0.2 Kg that is the mass of the bottle, and u2 is 0 that is the initial velocity of the bottle.
v1 is the final velocity of the ball, which is to be determined, and v2 is 25 m/s that is the final velocity of the bottle.
Substituting and rearranging the equation, one can find the final velocity of the ball:
v1 = m1u1 - m2v2 / m1 = (0.4 kg) (18 m/s) - (0.2 Kg) (25 m/s) / 0.4 Kg = 5.5 m/s.
I dont know the equation but you can look it up. It wont cost your points and it gives different equations that could work!
Answer: The relative error of the resulting quantity is 0.018.
Explanation: Relative error of the quantities when are multiplied together is usually less than or equal to the sum of each relative error. Mathematically, it is represented as
According to the question,
Let us assume that the three quantities are 
Taking log on both the sides, we get
Relative error is calculated by:
This value has 3 significant figures only, so the resulting relative error is 0.018.
Answer:
Average atomic mass of E = 103.57 amu
Explanation:
Given data:
Average atomic mass of E = ?
Abundance of E-102.658 = 56.67%
Abundance of E-104.770 = 43.33%
Solution:
Average atomic mass of E = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass of E = (56.67×102.658)+(43.33×104.770) /100
Average atomic mass of E = 5817.63 + 4539.68 / 100
Average atomic mass of E = 10357.31 / 100
Average atomic mass of E = 103.57 amu.
