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masha68 [24]
3 years ago
10

Carbon-14 undergoes radioactive decay in the reaction above. Determine the type of radiation emitted in this reaction and descri

be what is happening to the nucleus during this reaction.
Chemistry
2 answers:
nexus9112 [7]3 years ago
8 0

B.Beta radiation is emitted in this equation because the atomic number increases (from 6 to 7). This means a neutron has decayed into a proton, which occurs by emitting an electron, 0-1e.

The atomic mass number does not change because a beta particle has a much smaller mass than the atom. The atomic number goes up because a neutron has turned into an extra proton.

Drupady [299]3 years ago
4 0

<u>Answer:</u> The beta-particle is being released in the reaction and the nucleus is changing from to nitrogen.

<u>Explanation:</u>

Carbon-14 undergoes a radioactive decay by the process of beta-minus decay.

In beta-minus decay, a neutron gets converted to a proton and an electron.

The equation for the beta-minus decay of carbon-14 follows the reaction:

_6^{14}\textrm{C}\rightarrow _7^{14}\textrm{N}+_{-1}^0\beta

In this reaction beta-particle is being released carrying -1 charge. Another name for this particle is known as electron.

In this decay process, the nucleus is changing from carbon to nitrogen. The property of the nucleus is changing completely as number of protons is getting increased.

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In the diagram, an activity which is happening to the temperature at Point B is that: C. The temperature is not rising because the heat is being used to break the connections between the molecules.

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Matter can be defined as any physical object or body that has both mass and takes up space. This ultimately implies that, the mass of a physical object measures the amount of matter the object contains.

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By critically observing the diagram, we can reasonably infer and logically deduce that matter has dynamic states depending on the composition of its atoms and at point B the temperature remained constant (not rising) because the quantity of heat generated is used for breaking any form of connection between the molecules.

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8 0
1 year ago
A piece of unknown metal with mass 68.6 g is heated to an initial temperature of 100 °C and dropped into 84 g of water (with an
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8 0
3 years ago
Two solutions are created by mixing one solution containing lithium nitrate with one containing sodium phosphate.
babunello [35]

Answer:

Solution A that will form a precipitate with Ksp = 2.3 x 10−4

Explanation:

                                  Li₃PO₄ ⇄ 3 Li⁺(aq) + PO₄³⁻(aq)

                                                     3S               S

Where S = Solubility(mole/lit) and Ksp = Solubility product

⇒ Ksp = (3S)³ x (S)

⇒ 27S⁴ = 2.3x10−4

⇒ S = 0.05 mol/lit

Concentration of Li₃PO₄ precipitate = 0.05

<u>Solution A </u>

0.500 lit of a 0.3 molar LiNO₃ contains 0.5 x 0.3 = 0.15 mole

0.4 lit of a 0.2 molar Na₃PO₄ contains = 3 x 0.4 x 0.2 = 0.24 mole

                                     3 LiNO₃ + Na₃PO₄ → 3 NaNO₃ + Li₃PO₄

(Mole/Stoichiometry)    \frac{0.15}{3}                \frac{0.24}{1}

                                   = 0.05            = 0.24

Since from (Mole/Stoichiometry) ratio we can conclude that LiNO₃ is limiting reagent.

So concentration of Li₃PO₄ is equal to 0.05.

                       

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