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luda_lava [24]
3 years ago
13

The data part of Lab Hydrates in Edgunuity

Chemistry
1 answer:
FinnZ [79.3K]3 years ago
3 0

Answer:

Hydrates! :D

Explanation:

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I can't tell because I can't see the picture but it seems like
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In a carbon-carbon triple bond, what is the nature of the bonding between the carbons?
maxonik [38]
A triple bonded carbon is called an alkyne. (with a y, e for double bond, a for single bond)
4 0
3 years ago
Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
tekilochka [14]

Answer: There are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

So, the number of atoms present in 0.67 moles are as follows.

0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms

Thus, we can conclude that there are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

7 0
2 years ago
The volume of a single rhodium atom is 1.01×10-23 cm3. What is the volume of a rhodium atom in microliters?
Anni [7]

Answer: 1.01 x 10^20 microliters.

Explanation: volume is defined as a three-dimensional measure of space that comprises a length, a width and a height. In other words, we are asked to convert from one volumetric measure to another (cubic centimeters to microliters) —volume is measured in units of cubic centimeters in metric, cubic inches or cubic feet in English measurement.

If, 1 cm³ = 1000 uL (microliters) then,

1 uL - - - - - - - - - 0.001 cm³ = 1 x 10^-3 cm

x uL - - - - - - - - - 1.01×10^-23 cm³

Therefore,

x uL = 1.01 x 10^-23 cm³ / 0.001 cm³

x uL = 1.01 x 10^(-23 - - 3)

x uL = 1.01 x 10^( - 23 + 3)

x uL = 1.01 x 10^20

Which is to say that a single rhodium atom of volume 1.01 x 10^23 cm³ would occupy 1.01 x 10^20 microliters.

4 0
3 years ago
Which element in period 3 has both metallic and non metalik properties​
Andrei [34K]

Answer:

Si is the answer I hope this help

6 0
2 years ago
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