The heat absorbed to raise temperature : Q = 31350 J
<h3>Further explanation
</h3>
Given
m = mass = 150 g
Δt = Temperature difference : 50 °C
Required
Heat absorbed
Solution
Heat can be formulated
<em>
Q = m.c.Δt
</em>
The specific heat of water = c = 4.18 J/g °C
Input the value :
Q = 150 x 4.18 x 50
Q = 31350 J
Answer herbert
Explanation:
cause he did not do any of the safety precautions and he was prob not listening to the teacher
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