Answer:
- <u>Yes, it is 14. g of compound X in 100 ml of solution.</u>
Explanation:
The relevant fact here is:
- the whole amount of solute disolved at 21°C is the same amount of precipitate after washing and drying the remaining liquid solution: the amount of solute before cooling the solution to 21°C is not needed, since it is soluble at 37°C but not soluble at 21°C.
That means that the precipitate that was thrown away, before evaporating the remaining liquid solution under vacuum, does not count; you must only use the amount of solute that was dissolved after cooling the solution to 21°C.
Then, the amount of solute dissolved in the 600 ml solution at 21°C is the weighed precipitate: 0.084 kg = 84 g.
With that, the solubility can be calculated from the followiing proportion:
- 84. g solute / 600 ml solution = y / 100 ml solution
⇒ y = 84. g solute × 100 ml solution / 600 ml solution = 14. g.
The correct number of significant figures is 2, since the mass 0.084 kg contains two significant figures.
<u>The answer is 14. g of solute per 100 ml of solution.</u>
Hey there!
The correct answer is C) They all contain hydrogen. All acids contain hydrogen atoms.
Thank you!
21) Ionic
22) Ionic
23) Covalent
24) Ionic ?
25) Ionic
26) Ionic
27) Ionic ?
28) Covalent
29) Ionic ?
30) Covalent
31) Ionic ?
32) Ionic ?
33) Covalent
34) Ionic ?
35) Ionic ?
36) Covalent ?
37) Covalent
38) Ionic ?
39) Ionic ?
40) Covalent
These answers are based on if there was a nonmetal and nonmetal it’s Covalent and if there was a metal and nonmetal it was Ionic I didn’t use the electro negativity for the answers that has more than two elements, if the answers had more than two elements they have a ? Next to their answer.
I HOPE THIS HELPS AND IF IM WRONG FEEL FREE TO COMMENT AND TELL ME SO
Answer:
V₂ = 116126.75 cm³
Explanation:
Given data:
Radius of balloon = 15 cm
Initial pressure = 2 atm
Initial temperature = 35 °C (35 +273 = 308K)
Final temperature = -20°C (-20+273 = 253 K)
Final pressure = 0.3 atm
Final volume = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
Initial volume of balloon:
V = 4/3πr³
V = 4/3×22/7×(15cm)³
V = 14137.17 cm³
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 2 atm × 14137.17 cm³ × 253 K / 308 K × 0.3 atm
V₂ = 7153408.02 atm .cm³. K / 61.6 K.atm
V₂ = 116126.75 cm³
