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marusya05 [52]
3 years ago
11

Which events took place during the Copernican revolution, when most people started to believe in a heliocentric model of the sol

ar system? Check all that apply.
Aristotle developed his model of the solar system.

Copernicus rediscovered Aristarchus’s heliocentric model.

Hawking proposed theories that increased curiosity about space.

Scientists checked, confirmed, refined, and mathematically proved ideas.

Newton’s theories of gravity increased understanding of the movement of planets.
Physics
2 answers:
balu736 [363]3 years ago
7 0
<h2>2) Copernicus rediscovered Aristarchus’s heliocentric model.</h2>

Before Copernican Revolution, people did believe in the ptolemain model that establishes the description of the Universe with the earth at the center having sun, moon, starts and planets all orbited earth. On the other hand, the heliocentric model establishes the sun at the center of the solar system and this starts with the publication of Nicolas Copernicus named <em>De revolutionibus orbium coelestium.</em>

<h2>5) Newton’s theories of gravity increased understanding of the movement of planets.</h2>

The revolution ended with Isaac Newton's work over a century later. As you well know, Newton was both a physicist and mathematician, better known for his prodigal work called <em>Philosophiæ Naturalis Principia Mathematica. </em>In this revolution, he is known for his laws of motion and universal gravitation increasing understanding of the movement of planets.

Gekata [30.6K]3 years ago
4 0

Answer:

The correct option is B. Copernicus rediscovered Aristarchus’s heliocentric model.

Explanation:

Before the Copernican revolution, people believed that the Earth was present in the centre of the universe and it was stationary. This theory was then amended by Nicolaus Copernicus at the time of the Copernican revolution. He made models which showed the Sun to be the centre of the universe instead of the earth and other heavenly bodies to be rotating around the Sun. This model is known as the heliocentric model.

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If two temperatures differ by 25 degrees on Celsius scale, the difference of temperature on Fahrenheit scale is?
Mekhanik [1.2K]

Answer:

25 x 9/5 = 45 degrees Fahrenheit

Explanation:

4 0
2 years ago
The half-life of plutonium 239 is 24,200 years. Assume that the decay rate is proportional to the amount. Determine the amount o
kotykmax [81]

Answer:

time taken is equal to 14,156 years

Explanation:

we know,

Y=Ae^{-kt}

at t = 0

Y(0) = A

given that half life of plutonium 239 = 24,200

\dfrac{A}{2}=Ae^{-kt}\\0.5=e^{-kt}\\k\times 24200 = ln(2)\\k = \dfrac{ ln(2)}{24200}

Y=Ae^{-kt}

\frac{3}{2} = e^{-kt}\\ln(1.5)=-\dfrac{ ln(2)}{24200}\times t\\t=-\dfrac{ln(1.5)\times 24200}{ ln(2)}\\t=14,156 \ years

hence time taken is equal to 14,156 years

5 0
3 years ago
3) A bird flies toward a tree limb at a 45-degree angle to the ground along a path that is 50 m long landing on the limb. Determ
marin [14]

Answer:

35 m

Explanation:

Given :

The distance of the path from the ground to the tree limb = 50 m

The angle between the path of flight of the bird towards the tree limb and the ground = 45 degrees

Therefore we can determine the height above which the bird perched above the ground by using the rules of the trigonometric ratios as;

We know that ,

$\sin 45^\circ =\frac{\text{perpendicular}}{\text{hypothenus}}$

$\sin 45^\circ =\frac{\text{BC}}{\text{AC}}$

$0.7  =\frac{\text{BC}}{\text{50}}$

\text{BC }= 0.7 \times 50

       = 35

Therefore, the bird perched on the tree limb at a height of 35 m.

6 0
3 years ago
Suppose that during a storm the force of the wind blowing against a skyscraper can be expressed by the vector , where each measu
Andrei [34K]

Answer:

Here we do not have the vector, but I will try to give a kinda general solution to this type of problem.

If the vector is written as (a, b, c) we have that the force in the x-axis is of a Newtons, in the y-axis is of b Newtons, and in the z-axis is of c Newtons.

Then, we can calculate the total magnitude of this force as:

F = √( a^2 + b^2 + c^2)

wich gives us the total magnitude of the force, but not a direction or anything like that, this is just a scalar.

3 0
3 years ago
Read 2 more answers
A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hits the ground. From w
BaLLatris [955]

Answer:

The object fell from about 38.14 meters

Explanation:

We can use the formula for displacement under accelerated motion due to gravity to find the velocity of the object had 30 m before hitting the ground :

y_f-y_i=v_i * \,t-\frac{9.8}{2} \,t^2\\0-30=v_i \,(1.5)-4.9\,(1.5)^2\\-18.975=v_i\,(1.5)\\v_i=-12.65\,\,\frac{m}{s}

Now, knowing this velocity, we can find the time it took to fall from the initial position to 30 m before hitting the ground:

v_f=v_i-g\,*\,t\\-12.65=0-g \,*\,t\\t=\frac{12.65}{g} \\t\approx1.29\,\,s

And now we can find what is the total distance covered in 1.5 s plus 1.29 seconds for this free falling object:

y_f-y_i=v_i * \,t-\frac{9.8}{2} \,t^2\\0-y_i=0-\frac{9.8}{2} \,(2.79)^2\\-y_i=-38.14\\y_i=38.14\,\,m

7 0
3 years ago
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