Jessica has a mass of 55kg she sleds down a hill that has a slope of 32 degrees. what is the component of her weight that is alo
ng her direction of motion ?
2 answers:
Answer:
W = 285.62 N
Explanation:
It is given that,
Mass of Jessica is 55 kg
Slope of the hill is 32 degrees
We need to find the component of her weight that is along her direction of motion.
The component along her direction of motion is shown in attached figure. It means
So, the component of her weight that is along her direction of motion is 285.62 N.
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Answer:
a) 37171
b) sec
Explanation:
m = mass of the weight being lifted = 60.0 kg
d = distance by which the weight is lifted = 0.670 m
E = Energy available to burn = 1 lb = 3500 kcal = 3500 x 4184 J
g = acceleration due to gravity = 9.8 m/s²
n = number of times the weight is lifted
Energy available to burn is given as
E = n m g d
3500 x 4184 = n (60) (9.8) (0.670)
n = 37171
b)
T = time period for each lift up = 1.80 s
t = total time taken
Total time taken is given as
sec