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Nonamiya [84]
3 years ago
8

Heat can be transferred in several ways. Which of the following is an example of conduction? (DOK 2) A The sun is shining on a m

etal chair. B A fire in the fireplace is heating a room C Someone touching a hot metal pan DA hair dryer blowing your hair​
Physics
1 answer:
forsale [732]3 years ago
8 0

Answer:

Explanation:

G yvyvybybybububunununu

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clock

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According to the Law of Reflection, the angle of incidence
Elan Coil [88]

Answer:

A

Explanation:

this is because the law of reflection states that the angle of incidence equals to the angle of the reflection.

hope this helps, if not please report it

someone else can try it

8 0
2 years ago
Concave lens cause rays to _____.
Molodets [167]
Diverge or spread apart.
5 0
3 years ago
If you walk 1.2 km north and then 1.6 km east, what are the magnitude and direction of your resultant displacement?
vodomira [7]

<u>Answer:</u>

 Option A is the correct answer.

<u>Explanation:</u>

  Let the east point towards positive X-axis and north point towards positive Y-axis.

 First walking 1.2 km north,  displacement = 1.2 j km

 Secondly 1.6 km east, displacement = 1.6 i km

 Total displacement = (1.6 i + 1.2 j) km

 Magnitude = \sqrt{1.2^2+1.6^2} = 2 km

 Angle of resultant with positive X - axis = tan^{-1}(1.2/1.6)=36.87^0 = 36.87⁰ east of north.

 

5 0
3 years ago
An object is placed 18 cm in front of spherical mirror.if the image is formed at 4cm to the right of the mirror, calculate it's
ivolga24 [154]
1) Focal length

We can find the focal length of the mirror by using the mirror equation:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i} (1)
where 
f is the focal length
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

In this case, d_o = 18 cm, while d_i=-4 cm (the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:
\frac{1}{f}= \frac{1}{18 cm}- \frac{1}{4 cm}=- \frac{7}{36 cm}
from which we find
f=- \frac{36}{7} cm=-5.1 cm

2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.

3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.

4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is:
r=2f=2 \cdot 5.1 cm=10.2 cm
3 0
3 years ago
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