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german
3 years ago
12

1-D Kinematics

Physics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:

hope it helps you...........

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An elevator is moving upward at 0.91 m/s when it experiences an acceleration 0.31 m/s2 downward, over a distance of 0.61 m. What
alexgriva [62]

Given:

u= 0.91 m/s

a=0.31m/s∧2

s= 0.61 m

s = ut +1/2(at∧2)

where s is the displacement of the object

u is the initial velocity

t is the time

a is the acceleration

Substituting the values

0.61=0.91×t +(0.31 ×t∧2)/2

0.61=0.91 t + 0.155 t∧2

t=0.61 secs

Consider the equation

<u>v=u +at </u>

where v is the initial velocity

u is the initial velocity

a is the acceleration

t is the time

Substituting the values we get

v= 0.91 +(0.31×0.61)

v= 1.099 m/s


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4 years ago
A ________ is a device that converts digital signals from a computer into analog signals so that telephone lines may be used as
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Explanation:

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