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Anestetic [448]
3 years ago
6

Aluminium + hydrochloric acid =

Physics
1 answer:
anygoal [31]3 years ago
4 0

Answer:

Aluminum hydrochloric acid

Explanation:

Aluminum reacts with diluted hydrochloric acid at room temperature. The metal aluminium dissolves in hydrochloric acid, producing aluminum chloride and colorless hydrogen gas. The reaction taking place between aluminium and hydrochloric acid is irreversible. And the final products will not react with each other.

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A single-turn circular loop of radius 6 cm is to produce a field at its center that will just cancel the earth's field of magnit
djverab [1.8K]

Answer:

The current is  I  = 6.68 \  A

Explanation:

From the question we are told that  

     The radius of the loop is  r =  6 \ cm  = 0.06 \ m

     The  earth's magnetic field is B_e =  0.7G=  0.7  G * \frac{1*10^{-4} T}{1 G}  = 0.7 *10^{-4} T

      The  number of turns is  N  =1

Generally the magnetic field generated by the current in the loop is mathematically represented as

        B  =  \frac{\mu_o  * N  *  I}{2 r }

Now for the earth's magnetic field to be canceled out the magnetic field generated by the loop must be equal to the magnetic field out the earth

         B  =  B_e

=>     B_e =  \frac{\mu_o  *  N  *  I  }{ 2 * r}

     Where  \mu is the permeability of free space with value  \mu _o  =   4\pi * 10^{-7} N/A^2

       0.7  *10^{-4}=  \frac{ 4\pi * 10^{-7}  * 1 * I}{2 * 0.06}

=>     I  =  \frac{2 *  0.06 *  0.7 *10^{-4}}{ 4\pi * 10^{-7} * 1}

       I  = 6.68 \  A

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3 years ago
NEED HELP!!!!!! CAN SOMEBODY HELP ME?
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4 0
4 years ago
A falling back in mid air has what
Umnica [9.8K]
Acceleration I think if I’m not mistaken
4 0
4 years ago
A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 5.20 km. What is the plane's acceler
Tema [17]

Answer:

Acceleration of the plane, a = 5.4 g

Explanation:

It is given that,

Speed of the jet plane, v = 1890 km/h = 525 m/s

Radius of the arc, r = 5.20 km = 5200 m

The plane is moving in the circular path, the centripetal acceleration will act on it. It is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(525\ m/s)^2}{5200\ m}

a=53.004\ m/s^2

We know that, the value of g is, g=9.8\ m/s^2

\dfrac{a}{g}=\dfrac{53.004\ m/s^2}{9.8\ m/s^2}=5.4

a=5.4\times g

So, the acceleration of the plane is 5.4 g. Hence, this is the required solution.

6 0
3 years ago
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7 0
4 years ago
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