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3 years ago

HELP PLSSS how many licks does it take to get to the center of a tootsy pop?

Physics

2 answers:

bixtya [17]3 years ago

6 0

Answer:

364 licks

A group of engineering students from Purdue University reported that its licking machine, modeled after a human tongue, took an average of 364 licks to get to the center of a Tootsie Pop. Twenty of the group's volunteers assumed the licking challenge-unassisted by machinery-and averaged 252 licks each to the center.

Explanation:

Nat2105 [25]3 years ago

3 0

Answer:

364 licks

Explanation:

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The apparatus commonly used in the laboratory to show expansion on heating is the ring and_____apparatus

Nitella [24]

Answer:

ring and ball apparatus

Explanation:

In this experiment, the ball cannot pass through the ring due to its expansion, but the same ball can pass through the same ring when it is cooled down.

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Comets travel in orbits around the Sun. Some comets take less than 200 years to orbit the Sun. They are called short-period come

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3 years ago

Someone HELPPPPPPPPP MARKING BRAINLIST JUST CHECK WORK (15 points)

FromTheMoon [43]

Answer: I'm pretty sure you're right. Believe in yourself!

Explanation:

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3 years ago

A level test track has a coefficient of road adhesion of 0.80, and a car being tested has a coefficient of rolling friction that

pav-90 [236]

Answer:

the unloaded braking efficiency is 84.6 %

Explanation:

Given the data in the question;

by Ignoring aerodynamic resistance; we can find the theoretical stopping distance using the following formula

S = (Y $_{b}$ ( V₁² - V₂²)) / ( 2g( ηbμ + $f_{rl}$ ± sin∅ $_{g}$ ))

now given that the tracked is levelled, ∅ $_{g}$ = 0, also Y $_{b}$ = 1.04 for level or flat road

Speed V₁ = 60mil/hr = (60×5280)/(1×60×60) = 316800ft/3600s = 88ft/s

now, we substitute in our values to get the braking efficiency;

180ft = (1.04( (88ft/s)² - 0²)) / ( 2(32.2( (ηb/100)(0.80) + (0.018) ± sin(0°)))

180ft = 8053.76 / ( 64.4)(0.008ηb + 0.018)

180ft = 8053.76 / ( 0.5152ηb + 1.1592)

180( 0.5152ηb + 1.1592) = 8053.76

( 0.5152ηb + 1.1592) = 8053.76 /180

0.5152ηb + 1.1592 = 44.7431

0.5152ηb = 44.7431 - 1.1592

0.5152ηb = 43.5839

ηb = 43.5839 / 0.5152

ηb = 84.596 ≈ 84.6 %

Therefore, the unloaded braking efficiency is 84.6 %

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3 years ago

Why does the velocity change when the boy hits the ball

juin [17]

Answer:

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3 years ago

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