<u>Answer:</u> The theoretical yield of magnesium oxide is 6.65 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of magnesium = 4.00 g
Molar mass of magnesium = 24.3 g/mol
Putting values in equation 1, we get:
The given chemical equation follows:
By Stoichiometry of the reaction:
2 moles of magnesium produces 2 moles of magnesium oxide
So, 0.165 moles of magnesium will produce = of magnesium oxide
Now, calculating the theoretical yield of magnesium oxide by using equation 1:
Molar mass of magnesium oxide = 40.3 g/mol
Moles of magnesium oxide = 0.165 moles
Putting values in equation 1, we get:
Hence, the theoretical yield of magnesium oxide is 6.65 grams.