The ph before the addition of any Koh is<u> 10.105.</u>
Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.
After the addition of 50 ml KOH,
moles of KOH = 50 * 0.13 =<u> 6.5 mmol </u>
<u>moles </u><u>of HClO = 50 * 0.13 = 6.5 mmol </u>
occurred hydrolysis solution,
pH = 0.5(14 + pKa + log [base conjugate])
pH = 0.5(14 + (- log (4 * 10^-8)) + log (6.5/(50 + 50)))
pH = <u>10.105</u>
The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.
The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.
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The correct option is C.
It is very important as a nurse to ensure that one always create a complete and comprehensive documentation of the care given to a client. This has many advantages and one of it is that it will the give health providers that will be taken care of the patient in the future the necessary background information about the client. This will enable them to attend to the client properly based on his previous medial history.
Answer:
Hydration
Explanation:
In water, ions are surrounded by a sphere of water molecules called a hydration shell. The process of forming this shell is called hydration.
Answer:
![[I_2]=[Br]=0.31M](https://tex.z-dn.net/?f=%5BI_2%5D%3D%5BBr%5D%3D0.31M)
Explanation:
Hello there!
In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:
Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:
![K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BIBr%5D%5E2%7D%7B%5BI_2%5D%5BBr_2%5D%7D%20%5C%5C%5C%5C1.2x10%5E2%3D%5Cfrac%7B%282x%29%5E2%7D%7B%282.0-x%29%5E2%7D)
Thus, we solve for x as show below:
Therefore, the concentrations of both bromine and iodine are:
![[I_2]=[Br]=2.0M-1.69M=0.31M](https://tex.z-dn.net/?f=%5BI_2%5D%3D%5BBr%5D%3D2.0M-1.69M%3D0.31M)
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