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ICE Princess25 [194]
3 years ago
13

What is the potential energy of a 2-kg vase sitting on a table with a height of 1 meter?

Chemistry
1 answer:
lisov135 [29]3 years ago
7 0

"20 J" is the "Potential Energy" of "vase" on the table.  

<u>Explanation</u>:

The body possess some energy according to the position of the object that is the when an object is placed at a height it stores some energy it is called "Potential Energy".

Formula used to calculate the "Potential Energy" is m\times g \times h

Where, "m" is mass of vase is given that 2 kg, "g" is acceleration due to gravity is 10 m/s^2 and "h" is height of the object where it placed is 1 m.

Substitute the given values in the formula,

Potential energy of the vase = 2\times10\times1

Potential energy of the vase = 20 J

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Svetach [21]

The overall reaction is given by:

Br_{2}(g) + 2 NO(g) \rightarrow  2 NOBr(g)

The fast step reaction is given as:

NO(g) + Br_{2}(g) \rightleftharpoons NOBr_{2}(g) (fast; k_{eq}= \frac{k_{1}}{k_{-1}})

The slow step reaction is given as:

NOBr_{2}(g) + NO(g) \rightarrow  2 NOBr(g) (slow step k_{2})

Now, the expression for the rate of reaction of fast reaction is:

r_{1}=k_{1}[NO][Br_{2}]-k_{-1}[NOBr_{2}]

The expression for the rate of reaction of slow reaction is:

r_{2}=k_{2}[NOBr_{2}] [NO]

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as [NOBr_{2}] takes place in this reaction.

The expression of rate of formation is:

\frac{d(NOBr)}{dt}=r_{2}

= k_{2}[NOBr_{2}][NO]    (1)

Now, consider that the fast step is always is in equilibrium. Therefore, r_{1}=0

k_{1}[NO][Br_{2}]= k_{-1}[NOBr_{2}]

[NOBr_{2}] = \frac{k_{1}}{k_{-1}}[NO][Br_{2}]

Substitute the value of [NOBr_{2}] in equation (1), we get:

\frac{d(NOBr)}{dt}=k_{2}[NOBr_{2}][NO]

=k_{2} \frac{k_{1}}{k_{-1}}[NO][Br_{2}][NO]

= \frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]

Thus, rate law of formation of NOBr in terms of reactants is given by \frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}].









4 0
3 years ago
PLEASE HELP!!!! 20 MINS LEFT IM DYING PLS HELP
Zepler [3.9K]

Answer:

Kc = 0.20        

Explanation:

                  N₂O₄     ⇄    2NO₂

moles       5.3mol          2.3mol

Vol               5L                5L

Molarity    5.3/5M        2.3/5M

                = 1.06M     = 0.46M

Kc = [NO₂]²/[N₂O₄] =  (0.46)²/(1.06) = 0.1996 ≅ 0.20

6 0
3 years ago
What method is used for chaff from grain<br>​
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Answer:

Winnowing

Explanation:

Wind blows the lighter(in terms of mass) chaff from the whole grains,which are heavier(in terms of mass)

4 0
2 years ago
In the covalent bond between hydrogen and chlorine in the HCl molecule, where will the majority of shared electrons be found?
Mrac [35]
Nearer to the chlorine as it has a greater electronegativity 
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The disaccharide lactose can be decomposed into its constituent sugars galactose and glucose. This decomposition can be accompli
n200080 [17]

Answer:

Rate  = 116m⁻¹s⁻¹[lactose][H]⁺

Explanation:

the formula for rate of reaction is given as

Rate = k[lactose]∧α[H]⁺∧β

we solve for the value of α and β

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α = \frac{ln\frac{0.00116}{0.00232} }{ln\frac{0.01}{0.02} }

when we divide this equation

α = \frac{ln0.5}{ln0.5}

α = 1

we find β

R₁/R₂ = 0.01/0.02(0.001/0.001)∧β

0.00116/0.00232 = 0.5(1)∧β

β = 1

Rate = k[lactose]∧α[H]⁺∧β

we have to find the value for k

k = 0.00116/0.01(0.001)

k = 0.00116/0.00001

= 116m⁻¹s⁻¹

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