You don't include the charges in formulas.
It is your test we can't help you if you have any homework so we can
Answer:
The hydrogen ion concentrations associated with these pH value 7.35 is 
The hydrogen ion concentrations associated with these pH value 7.45 is 
.
Explanation:
To calculate the pH of the solution, we use the equation:
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
We are given:
1) pH = 7.35
Putting values in above equation, we get:
![7.35=-\log[H^+]](https://tex.z-dn.net/?f=7.35%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=4.467\times 10^{-8} M\approx 4.5\times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D4.467%5Ctimes%2010%5E%7B-8%7D%20M%5Capprox%204.5%5Ctimes%2010%5E%7B-8%7D%20M)
The hydrogen ion concentrations associated with these pH value 7.35 is
2) pH = 7.45
Putting values in above equation, we get:
![7.45=-\log[H^+]](https://tex.z-dn.net/?f=7.45%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=3.548\times 10^{-8}M \approx 3.6\times 10^{-8} M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D3.548%5Ctimes%2010%5E%7B-8%7DM%20%5Capprox%203.6%5Ctimes%2010%5E%7B-8%7D%20M)
The hydrogen ion concentrations associated with these pH value 7.45 is .
Answer:
b All of them are highly reactive nonmetals
Answer:
by providing an alternative pathway with a lower activation energy
Explanation:
Cataysts are the substances that neither consumed nor produced during a chemical reaction, but increase the rate of the reaction.
So, catalysts remain chemically unchnaged after the completion of the reaction.
For a reaction to occur, reactants molecule must collide and successful collisions lead to product formation.
A certain minimum amount of energy is required for successful collision. This minimum amounr of energy is called activation energy.
One way to increase speed of reaction is to provide energy to the reactants and other way to increase speed is to provide alternate pathway with lower activation energy.
Catalyst increases a rate of reaction by providing an alternate pathway with lower activation energy.
Therefore, the correct option is option b 'by providing an alternative pathway with a lower activation energy'
