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I believe the answer would be A. equal temperature
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Answer:
The new pressure of the gas comes out to be 400 KPa.
Explanation:
Initial volume of gas = V =
Initial pressure of gas = P = 120 KPa
Final volume of gas = V' =
Assuming temperature to be kept constant.
Assuming final pressure of the gas to be P' KPa

New pressure of gas = 400 KPa
The solubility equilibrium of
:
[tex] CaCrO_{4}(aq)<===>Ca^{2+}(aq) + CrO_{4}^{2-}(aq)\\
Q_{sp}=[Ca^{2+}][CrO_{4}^{2-}]\\
= (0.0200 M)(0.0300 M) \\
= 0.0006
Ksp (0.00071) > Qsp (0.0006). So, <u>no precipitate would form</u>.