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ANTONII [103]
3 years ago
14

Jasmine has toast for breakfast every day. As soon as the toast pops out of the toaster, she puts butter on it. If she does it q

uickly, she can spread the butter over the toast with her knife, and it melts into the toast. Why does the butter melt? A. Because the pressure of her knife softens the butter B. Because heat from Jasmine's hand moves into the cool butter C. Because heat from the hot knife moves into the cool butter D. Because heat from the hot toast moves into the cool butter
Chemistry
1 answer:
andrew-mc [135]3 years ago
6 0

The answer is D. because heat from the hot toast moves into the cool butter

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What mass (in g) of potassium chlorate is required to supply the proper amount of oxygen needed to burn 117.3 g of methane
Brilliant_brown [7]

The mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

<h3>Combustion of methane</h3><h3 />

Methane burns in oxygen to produce carbon (iv) oxide and water according to the equation of the reaction below:

CH₄ + 2O₂  ----> CO₂ + 2H₂O

1 mole of methane requires 2 moles of oxygen for complete combustion

1 mole of methane has a mass of 16 g

moles of methane in 117.3 g = 117.3/16 = 7.33 moles of methane

7.33 moles of methane will require 2 * 7.33 moles of oxygen

7.33 moles of methane will require 14.66 moles of oxygen

<h3>Decomposition of potassium chlorate </h3>

The decomposition of potassium chlorate produces oxygen

The equation of the reaction is given below:

  • 2KClO3 → 2KCl + 3O2.

2 moles of potassium chlorate produces 3 moles of oxygen

14.66 moles of oxygen will be produced by 14.66 * 2/3  moles of potassium chlorate

14.66 moles of oxygen will be produced by 9.77 moles of potassium chlorate

1 mole of  potassium chlorate has a mass of 122.5

9.77 moles of potassium chlorate has a mass of 1196.82 g

Therefore, the mass (in g) of potassium chlorate required to supply the proper amount of oxygen needed to burn 117.3 g of methane is 1196.82 g

Learn more about mass and molar mass at: brainly.com/question/15476873

7 0
3 years ago
What is the concentration of agcl in an aqueous solution that contains 1.2 x 10-3 gram of agcl in 800. grams of the solution? 1.
Vlada [557]
Concentration can be measured in ppm. ppm means parts mer million. In terms of mass , ppm units are mg/kg. 
concentration of AgCl solution is the mass of AgCl solute in mg per 1 kg of solution. 
mass of AgCl present = 1.2 x 10⁻³ kg = 1.2 mg
mass of solution = 800 g = 0.800 kg
the mass of AgCl in 0.800 kg of solution  = 1.2 mg
therefore mass of AgCl in 1 kg of solution = 1.2 mg / 0.800 kg x 1 kg = 1.5 mg
concentration of AgCl is 1.5 mg/kg
since mg/kg = ppm 
concentration of AgCl = 1.5 ppm
answer is 1.5 ppm
3 0
4 years ago
How do you determine the volume of an irregular object if you don't know the density?
Galina-37 [17]

Answer:

You can find the volume of an irregular object by immersing it in water in a beaker or other container with volume markings, and by seeing how much the level goes up.

Explanation:

8 0
4 years ago
An unknown solution has a pH of 7.2. Which of these chemicals is likely to cause the greatest decrease in the pH of the solution
monitta

Answer:

HNO₃.

Explanation:

  • It is known that acids decrease the pH of the solution, while bases increase  the pH of the solution.

So, HF and HNO₃ decrease the pH of the solution as they produce H⁺ in the solution.

<em>While, KOH and NH₃ increase the pH of the solution as they produce OH⁻ in the solution.</em>

<em />

HNO₃ will decrease the pH of the solution greater than HF.

  • Because HNO₃ is strong acid that decomposes completely to produce H⁺ more than the same concentration of HF that is a weak acid which does not decomposed completely to produce H⁺.
4 0
3 years ago
Read 2 more answers
How many grams of sodium formate, NaCHO2, would have to be dissolved in 3.0 L of 0.12 M formic acid (pKa 3.74) to make the solut
kolbaska11 [484]

Answer:

Mass_{sodium\ formate}= 889.57\ g

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the acidic buffer solution as:

pH=pK_a+log\frac{[salt]}{[acid]}

Given that:-

[Acid] = 0.12 M

Volume = 3.0 L

pKa = 3.74

pH = 5.30

So,  

5.30=3.74+log\frac{[sodium\ formate]}{0.12}

Solving, we get that:-

[Sodium formate] = 4.36 M

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

So,

Moles =Molarity \times {Volume\ of\ the\ solution}

So, Moles of sodium formate = 4.36*3.0 moles = 13.08 moles

Molar mass of sodium formate = 68.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

13.08\ mole= \frac{Mass}{68.01\ g/mol}

Mass_{sodium\ formate}= 889.57\ g

5 0
4 years ago
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