Answer:
Mass = 101891.2 g
Explanation:
Given data:
Mass of ammonia needed = ?
Mass of ammonium sulfate produced = 396 Kg = 396 ×1000 = 396000 g
Solution:
Chemical equation:
2NH₃ + H₂SO₄ → (NH₄)₂SO₄
Number of moles of (NH₄)₂SO₄:
Number of moles = mass/molar mass
Number of moles = 396000 g / 132.14 g/mol
Number of moles = 2996.8 mol
Now we will compare the moles of ammonia and ammonium sulfate
(NH₄)₂SO₄ : NH₃
1 : 2
2996.8 : 2/1×2996.8 = 5993.6 mol
Mass of ammonia needed:
Mass = number of moles × molar mass
Mass = 5993.6 mol × 17 g/mol
Mass = 101891.2 g
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Answer is: 8568.71 of baking soda.
Balanced chemical reaction: H₂SO₄ + 2NaHCO₃ → Na₂SO₄ + 2CO₂ + 2H₂O.
V(H₂SO₄) = 17 L; volume of the sulfuric acid.
c(H₂SO₄) = 3.0 M, molarity of sulfuric acid.
n(H₂SO₄) = V(H₂SO₄) · c(H₂SO₄).
n(H₂SO₄) = 17 L · 3 mol/L.
n(H₂SO₄) = 51 mol; amount of sulfuric acid.
From balanced chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 :2.
n(NaHCO₃) = 2 · 51 mol.
n(NaHCO₃) = 102 mol, amount of baking soda.
m(NaHCO₃) = n(NaHCO₃) · M(NaHCO₃).
m(NaHCO₃) = 102 mol · 84.007 g/mol.
m(NaHCO₃) = 8568.714 g; mass of baking soda.
Solution
Given mass of FeBr2 = 85.5 g
Molar mass of FeBr2 = 215.65
No. of Moles of FeBr2 = Given Mass / Molar mass = 85.5 / 215.65
No. of Moles = 0.3964
Given Volume is 450 mL i.e. 0.450 L
Now Concentration = 0.3964/0.450
Hence Concentration = 0.881 mol/L
Answer:
Fe₂O₃ + 3Zn → 2Fe + 3ZnO
Explanation:
Step 1: RxN
Fe₂O₃ + Zn → Fe + ZnO
Step 2: Balance RxN
We need 2 Fe's on both sides.
We also need 3 O's on both sides.
- If we multiply ZnO by 3, we will need 3 Zn's as well
Fe₂O₃ + 3Zn → 2Fe + 3ZnO
