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3 years ago

The smallest particle of a covalently bonded compound is a(n) ________.

Chemistry

2 answers:

vazorg [7]3 years ago

8 0

The smallest particle of a covalently bonded compound is an atom.

sdas [7]3 years ago

8 0

I think the correct answer from the choices listed above is option C. The smallest particle of a covalently bonded compound is a molecule. Molecules<span> are made up of atom s that are held together by chemical bonds. Hope this answers the question.</span>

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List 6 uses of acids

devlian [24]

Answer: 1. Vinegar, used in the kitchen, is a liquid containing 3-6% acetic acid. It is used in pickles and in many food preparations.

2. Lemon and orange juice contains citric acid. Citric acid is used in the preparation of effervescent salts and as a food preservative.

3. Acids have been put to many uses in industry. Nitric acid and sulphuric acid are used in the manufacture of fertilizers, dyes, paints, drugs and explosives.

4. Sulphuric acid is used in batteries, which are used in cars, etc. Tannic acid is used in the manufacture of ink and leather.

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2 years ago

What are the carbon (C) and oxygen (O) in carbon dioxide (CO2)?

Fynjy0 [20]

A. Atoms. Because I learned this in 6th grade.

6 0

2 years ago

One type of cat has the scientific name Felis domesticus, while another type of cat is called Felis tigris. What can be correctl

kykrilka [37]

A is the correct answer

3 0

3 years ago

One disadvantage of burning propane (C3H8) is that carbon dioxide is one of the products. The released CO2 increases the growing

Hoochie [10]

Answer:

80 MOLES OF WATER ARE PRODUCED WHEN 20 MOLES OF PROPANE ARE BURNED IN EXCESS OXYGEN ON A GAS GRILL.

Explanation:

Equation for the reaction:

C3H8 + 5 O2 ---------> 4 H2O + 3 CO2 + Heat

The above equation is in the presence of excess oxygen.

In this reaction,

1 mole of propane forms 4 moles of H2O

If 20 moles of propane were to be used, how many moles of water will be produced?

1 mole of propane = 4 moles of water

20 moles of propane = ( 4 * 20 ) moles of water

= 80 moles of water.

So, if 20 moles of propane were burned in excess oxygen, 80 moles of water will be formed. Propane is heavier than air and when properly combusted produces a large amount of heat. It is also non toxic.

6 0

2 years ago

Problem Page Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 70. g of

shusha [124]

Answer:

The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}

Explanation:

1. Write down the balanced chemical reaction:

$2C_{6}H_{14}_{(l)}+19O_{2}_{(g)}=12CO_{2}_{(g)}+14H_{2}O_{(g)}$

2. Find the limiting reagent:

- First calculate the number of moles of hexane and oxygen with the mass given by the problem.

For the hexane:

$70.0gC_{6}H_{14}*\frac{1molC_{6}H_{14}}{86.2gC_{6}H_{14}}=0.81molesC_{6}H_{14}$

For the oxygen:

$81.3gO_{2}*\frac{1molO_{2}}{32.0gO_{2}}=2.54molesO_{2}$

- Then divide the number of moles between the stoichiometric coefficient:

For the hexane:

$\frac{0.81}{2}=0.41$

For the oxygen:

$\frac{2.54}{19}=0.13$

- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.

3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:

The calculations must be done with the limiting reagent, that is the oxygen.

$81.3gO_{2}*\frac{1molO_{2}}{32gO_{2}}*\frac{12molesCO_{2}}{19molesO_{2}}*\frac{44.0gCO_{2}}{1molCO_{2}}=70.6gCO_{2}$

7 0

3 years ago