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const2013 [10]
3 years ago
9

Compare the densities of two objects that have the same volume, but one feels heavier than the other.

Physics
1 answer:
motikmotik3 years ago
8 0
We know, density = Mass / Volume
It represents density is directly proportional to mass and indirectly proportional to volume. So, at a constant volume, object with larger density will appear more heavier than that of object with smaller density.

In short, Heavier object will have the higher density than the other.

Hope this helps!
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The heart working with the blood vessels to pump blood is which body system?
LiRa [457]
I think it’s the cardiovascular system
6 0
3 years ago
Look at the graph. What is the slope of the line?
NeTakaya

For the first hour, the slope is zero.

After that, the slope is -2 miles per hour.

7 0
2 years ago
Which quantum number gives the approximate energy of an electron in the quantum mechanical model of the atom? A) n B) I C) m1 D
alexdok [17]

Answer:

Option A) n

Explanation:

In accordance to Quantum Mechanical model of an atom:

  • The Principle Quantum number (n) gives the description of the shell of an electron and the energy level of an electron in an atom.
  • The angular momentum also referred to as Azimuthal Quantum number (l) gives the description of  the shape of the orbitals and helps in determination of angular momentum magnitude.
  • The magnetic quantum number (m_{1}) describes the energy levels or the number of orbitals contained in a subshell and the way these are oriented within.
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4 0
3 years ago
A circular pipe of 25-mm outside diameter is placed in an airstream at 25C and 1-atm pressure. The air moves in cross flow over
kifflom [539]

Answer:

f_D = =3.24 N/m

Explanation:

data given

properties of air\nu\ of air =19.31*10^{-6} m2/s

\rho = 1.048 kg/m3

k = 0.0288 W/m.K

WE KNOW THAT

Reynold's number is given as

Re =\frac{VD}{\nu}

      = \frac{ 15*0.025}{19.31*10^{-6}}

      = 1.941 *10^4

drag coffecient is given as

C_D = \frac{f_D}{A_f\frac{\rho v^2}{2}}

solving for f_D

f_D = C_D A_f*\frac{\rho v^2}{2}

     =C_D D*\frac{\rho v^2}{2}

Drag coffecient for smooth circular cylinder is 1.1

therefore Drag force is

f_D = 1.1*0.025 *\frac{1.048*15^2}{2}

f_D = =3.24 N/m

4 0
3 years ago
A 75 kV x-ray machine gives an exposure of 200 mR for a 0.2-sec chest x-ray exam.
pashok25 [27]

Explanation:

Given that,

Potential = 75 kV

Exposure = 200 mR

Time = 0.2 sec

We need to calculate the x-ray fluence during this chest x-ray exam

Using formula of fluence

x-ray\ fluence=exposure\times time

Put the value into the formula

x-ray\ fluence=200\times0.2

x-ray\ fluence=40\ mRs

We need to calculate the energy fluence

Using formula of energy fluence

E_{f}=40\times10^{-3}\times75\times10^{3}

E_{f} = 3000\ J

We need to calculate dose -equivalent delivered to the bone, muscle, and fat

Using formula of dose

D=\dfrac{E}{t}

Where, D = dose

E = energy

t = time

Put the value into the formula

D=\dfrac{3000}{0.2}

D=15.0\ kJ

Hence, This is the required solution.

7 0
3 years ago
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