Answer:
10
Step-by-step explanation:
yup that's all have sorry
12! = 12x11x10x9x8x7x6x5x4x3x2x1 =479,001,600
3! = 3x2x1 =6
13! = 6,227,020,800
6,227,020,800 x 6 = 37,362,124,800
479,001,600/37,362,124,800=0.0128
Answer:
See below.
Step-by-step explanation:
Party A
y = x^2 + 1
For each value of x in the table, substitute x in the equation with that value and evaluate y.
x = -2: y = (-2)^2 + 1 = 4 + 1 = 5
x = -1: y = (-1)^2 + 1 = 1 + 1 = 2
Do the same for x = 0, x = 1, x = 2
x y
-2 5
-1 2
0 1
1 2
2 5
Part B
Look at points (-2, 5) and (-1, 2). The change in x from (-2, 5) to (-1, 2) is 1. The change in y is -3.
Now let's look at two other points which have a change in x of 1. Look at points (0, 1) and (1, 2). The change in x from (0, 1) to (1, 2) is 1. The change in y is 1.
You can see that for the first two points, a change of 1 in x produces a change of -3 in y, but for the second two points, the same change of 1 in x produce a change of 1 in y. Since the same change of x does not always produce the same change in y, the function is nonlinear.
Answer: A
Answer:
22 x^2
Step-by-step explanation:
Simplify the following:
11 x^2 + 11 x^2
Hint: | Add like terms in 11 x^2 + 11 x^2.
11 x^2 + 11 x^2 = 22 x^2:
Answer: 22 x^2
none of your answers are correct.
Answer:
Therefore you can wear your rings in =336 ways
Step-by-step explanation:
Multiplication Law: If one occurs in x ways and second event occurs in y ways.Then the number of ways that two event occur in sequence is xy
Given that you have 3 different rings.
We have total 10 figures.
But you don't wear ring on your thumbs.
We have 2 thumbs.
So you can wear rings on (10-2) = 8 figures.
The ways of wearing of first ring is = 8
The ways of wearing of second ring is = 7
The ways of wearing of third ring is = 6
Therefore you can wear your rings in =(8×7×6)
=336 ways
