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Gelneren [198K]
2 years ago
8

What was the contribution of Dobereiner towards classification of elements?​

Chemistry
2 answers:
Liono4ka [1.6K]2 years ago
6 0

<em>that the relative atomic mass of the middle element in each triad was close to the average of the relative atomic masses of the other two elements.</em>

  • <em>This gave other scientists a clue that relative atomic masses were important when arranging the elements.</em>

<h2><em>hope</em><em> </em><em>it</em><em> </em><em>helps!</em></h2>
Kitty [74]2 years ago
6 0

<em><u /></em><em><u>In 1829, Johann Döbereiner recognised triads of elements with chemically similar properties, such as lithium, sodium and potassium, and showed that the properties of the middle element could be predicted from the properties of the other two</u></em>.

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Identify the number of significant figures in each measurement.
Zepler [3.9K]
0.052301= 6 sig. figure
400 cm. = 3 significant figures
50.0. =. 3. Significant figure
4500.01=. 6 significant figure
7 0
3 years ago
Which of the following is NOT a possible end-product of a fermentation process?- glucose- carbon dioxide- lactic acid- ethanol
MArishka [77]

Answer:

glucose

Explanation:

There are two types of respiration:

1. Aerobic respiration  

2. Anaerobic respiration

Aerobic respiration:

It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.

Glucose + oxygen → carbon dioxide + water + 38ATP

Anaerobic Respiration:

It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.  

Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide

This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.  

Steps involve in anaerobic respiration are:

Glycolysis:

Glycolysis is the first step of both aerobic and anaerobic respiration. It involve the breakdown of one glucose molecule into pyruvate and 2ATP.

Fermentation:

The second step of anaerobic respiration is fermentation. It involve the fermentation of pyruvate into lactic acid or alcohol depending upon the organism in which it is taking place. There is no ATP produced in this step, however carbon dioxide is released.

4 0
4 years ago
Who know the answer
bekas [8.4K]

First, let's explain the variables. F means force, m means mass, and a means acceleration. F is measured in Newotns [N], mass is measured in kilograms [kg], and acceleration in measured in meters per squared second [m/s²].

Now let's mover on the first problem.

Given

m = 1000 kg

a = 3 m/s²

According to the second law of Newton, the force is equal to the acceleration multiplied by the mass.

F = am\\F = 3 * 1000\\F = 3000 N

The answer is 3000 N.

The second problem is smiliar.

Given

m = 70 kg

F = 250 N

We use the same formula from before, and use a bit of algebra to adapat it to our needs.

F = ma\\\frac{F}{m} = a\\a = \frac{F}{m}\\a = \frac{250}{70} \\a = 24\frac{1}{7} m/s^{2}

The answer is 24 1/7 s/m^2.

6 0
4 years ago
A soft drink contains 63 g of sugar in 378 g of H2O. What is the concentration of sugar in the soft drink in mass percent
Doss [256]

Answer:

\% m/m= 14.3\%

Explanation:

Hello,

In this case, the by mass percent is computed as shown below:

\% m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%

Whereas the solute is the sugar and the solvent the water, therefore, the concentration results:

\% m/m=\frac{63g}{63g+378g} *100\%\\\\\% m/m= 14.3\%

Best regards.

3 0
3 years ago
Determine the amount of heat energy in joules required to raise the temperature of 7.40g of water from 29.0OC to 46.0 OC.
valina [46]

Answer: The amount of heat energy in joules required to raise the temperature is 526 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed = ?

m= mass of substance = 7.40 g

c = specific heat capacity = 4.184J/g^0C

Initial temperature of the water = T_i = 29.0°C

Final temperature of the water = T_f  = 46.0°C

Change in temperature ,\Delta T=T_f-T_i=(46.0-29.0)^0C=17.0^0C

Putting in the values, we get:

Q=7.40g\times 4.184J/g^0C\times 17.0^0C

Q=526J

The amount of heat energy in joules required to raise the temperature is 526 Joules

4 0
3 years ago
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