Answer:
THE SPECIFIC HEAT OF THE ALLOY IS 0.9765 J/g K
Explanation:
Mass of alloy = 33 g
Initial temperature of alloy = 93°C
Mass of water = 50 g
Initail temp. of water = 22 °C
Heat capacity of calorimeter = 9.20 J/K
Final temp. = 31.10 °C
specific heat of alloy = unknown
specific heat capacity of water = 4.2 J/g K
Heat = mass * specific heat * change in temperature = m c ΔT
Heat = heat capcity * chage in temperature = Δ H * ΔT
In calorimetry;
Heat lost by the alloy = Heat gained by water + Heat of the calorimeter
mc ΔT = mcΔT + Heat capacity * ΔT
33 * C * ( 93 - 31.10) = 50 * 4.2 * ( 31.10 -22) + 9.20 * ( 31.10 -22)
33 * C * 61.9 = 50 * 4.2 * 9.1 + 9.20 * 9.1
2042.7 C = 1911 + 83,72
C = 1911 + 83.72 / 2042.7
C = 1994.72 /2042.7
C =0.9765 J/g K
The specific heat of the alloy is 0.9765 J/ g K
Answer:
here is definition with example
The answers to this problem is C
Answer:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
Explanation:
There are many ways to balance a chemical equation. In this case, I will show you the algebraic method:
The first step is assign a letter to each compound:
a Fe₂O₃ + b CO → c Fe + d CO₂
Then, you must write the balance equations for each atom, thus:
<em>Fe: 2a = c</em>
<em>C: b = d</em>
<em>O: 3a + b = 2d</em>
The last step is assign a value to a letter. I, for example, will say that <em>a is 1, </em>and then find the values for the others letters, thus:
<em>Fe: 2a = c </em>if <em>a=1; c=2</em>
<em>O: 3a + b = 2d </em>if <em>a=1 → 3+b = 2d</em>
As b = d → <em>3+d = 2d; 3 = 2d - d; </em>3=d and 3=b
Thus, the balanced equation is:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
I hope it helps!
Answer:
b) Industrial farming
Explanation:
The term “industrial agriculture” refers to the type of farming which raises and cultivates large numbers of livestock and plants in high-density environments. It uses modern technology to promote faster growth and reduce illness and death rates in livestock, creating food products on a mass scale.
