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Hoochie [10]
3 years ago
9

What is the definition of RNAMessenger RNAand Ribosome?​

Chemistry
1 answer:
IceJOKER [234]3 years ago
4 0
You can find this on google easily
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3 years ago
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H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.06×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.18×10−19, what is the equilibrium constant Kfinal for
serg [7]

Answer:

Therefore the equilibrium constant  K_{final} is 9.35× 10²⁵

Explanation:

Equilibrium constant:

Equilibrium constant is used to find out the ratio of the concentration of the product to that of reactant.

xA+yB→zC

The equilibrium constant K,

k=\frac{[C]^z}{[A]^x[B]^y}

Here [A] is equilibrium concentration of A

[B] is equilibrium concentration of B

[C] is equilibrium concentration of C.

1.  H_2S(aq)\rightleftharpoons HS^-(aq)+H^+(aq)          K_1= 9.06 \times 10^{-8}

K_1=\frac{[HS^-][H^+]}{[H_2S]}

2.   HS^-(aq)\rightleftharpoons S^{2-}(aq)+H^+(aq)      K_2= 1.18 \times 10^{-19}

K_2=\frac{[S^{2-}][H^+]}{[HS^-]}

3.

S^{2-}(aq)+2H^+(aq)\rightleftharpoons  H_2S(aq)

K_3=\frac{[H_2S]}{[S^{2-}][H^+]^2}

Therefore,

k_1k_2=\frac{[HS^-][H^+]}{[H_2S]}\frac{[S^{2-}][H^+]}{[HS^-]}

\Rightarrow k_1k_2=\frac{[S^{2-}][H^+]^2}{[H_2S]}

\Rightarrow k_1k_2=\frac{1}{K_3}

\Rightarrow K_3=\frac{1}{K_1K_2}

\Rightarrow K_3=\frac{1}{9.06\times 10^{-8}\times 1.18\times 10^{-19}}

⇒K₃=9.35× 10²⁵

K_3=K_{final}          

Therefore the equilibrium constant  K_{final} is 9.35× 10²⁵

3 0
3 years ago
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