Question

Solid aluminum (Al) and chlorine (C1,) gas react to form solid aluminum chloride (A1CI2). Suppose you have 7.0 mol of Al and 1.0 mol of Cl, in a reactor. Suppose as much as possible of the Al reacts. How much will be left? Round your answer to the nearest 0.1 mol.

Answer 1

Answer:

6.3 moles

Explanation:

From the balanced equation of reaction:

$2Al + 3Cl_2 --> 2AlCl_3$

2 moles of aluminium reacts with 3 moles of chlorine gas to form 2 moles of AlCl3.

Therefore, 1 mole of chlorine will require: 2 x 1/3 = 0.67 mole of aluminium.

Hence, 0.67 mole of aluminium will be needed for 1 mole of chlorine. If 7 moles of aluminium is present, then:

   7 - 0.67 = 6.33 moles of aluminium will be left.

To the nearest 0.1, it means 6.3 moles of aluminium will be left.