(i) The area of the cross section ABCDEFG is 1771.6cm³
(ii) The volume of the concrete lab is 212592 cm³
(iii) the total surface area of the concrete slab is 30284 cm²
(iv) The mass of the concrete slab is 40746.8 kg/m³.
Given, dimensions are 120 cm by 60 cm by
40 cm.
(i) area of cross section = 40 × 60 ₋ π(60 ₋10 ₋ 10)/2 . 1/2
= 1771.6 cm³
(ii) the volume of the concrete slab = 40 × 60 × 120 ₋ 1/2 π((60 ₋ 10 ₋10)/2)² . 120
= 212592 cm³
(iii) The total surface area is:
=40 × 120 × 2 ₊ 60 × 120 ₊ 1771.6 × 2 ₊ 10 × 120 × 2 ₊ 1/2 π(60 ₋ 10 ₋10) × 120
= 30284 cm²
(iv) Mass of the concrete slab given density is 2300 kg/m³
Mass = Volume × density
Mass = 17.716 m³ × 2300
= 40746.8 kg/m³
Hence we get the mass as 40746.8 kg/m³.
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I got -307 (if the x stands for multiplication)
Answer:
length=16feet width=12feet
Step-by-step explanation:
This may not be the best way, i just stumbled upon the answer using this.
I knew 14*14=196, which is relatively close to 192.
Then, I took away 2 from one of the 14s and added it to the other 14.
14-2=12 14+2=16
Apparently, 16*12 is 192, so that's the answer.
Answer:
f(x) = 8(x-3)
Step-by-step explanation:
F^ -1 ( x) = x/8 +3
Let y = x/8+3
To find the inverse
Exchange x and y
x = y/8+3
Solve for y
x-3 = y/8+3-3
x-3 = y/8
Multiply each side by 8
8(x-3) = y/8 * 8
8(x-3) = y
The inverse of the inverse is the function so
f(x) = 8(x-3)
43.0810
Since the hundred thousandths is a 1 which is less than a 5, you have to round down.