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nydimaria [60]
3 years ago
13

Which inequalities are true? Check all that apply.

Mathematics
1 answer:
garri49 [273]3 years ago
4 0

Answer: A , B, C, E

Step-by-step explanation:√4 = 2√5 = 2.24√5.5 = 2.36√6 = 2.45√8 = 2.83√9 = 3

A)√5 < 2.3<√62.24 < 2.3 < 2.45 True

B)√5 < 2.4<√62.24 < 2.4 < 2.45 True

C)√4 < √5 < √5.52 < 2.24 < 2.36 True

D)√8 < 3 < √92.83 < 3 < 3 False

E)√8 < 2.9 < √92.83 < 2.9 < 3 True

F)√4 < 4.5 < √52 < 4.5 < 2.24 False

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Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
How do you find each measure for #7?
Lunna [17]

Step-by-step explanation:

From this figure TUW+WUV=TUV ; (5x+3)+(10x-5)=17x-16 so 15x-2=17x-16 ;14=2x therefore x=7

then substitute x on it.

TUW=5x+3=5(7)+3=35+3=38

WUV=10x-5=10(7)-5=70-5=65

TUV=17x-16=17(7)-16=119-16=103

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Step by step:
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