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3 years ago

Anyone know how to do this!?

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

3 0

Answer:

nope

Step-by-step explanation:

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Several million lottery tickets are sold, and 21% of the tickets are held by men. Suppose you select a random sample of people a

valina [46]

Answer:

hypergeometric

Step-by-step explanation:

For each winning ticket, there are only two possible outcomes. Either it is held by a men, or it is not.

There is a set number of X, and as the number of winning tickets decrease, the probability of a winning ticket being held by a men can decrease or increase. This is a characteristic of the hypergeometric distribution.

5 0

2 years ago

Let F(X) = x^2-16x+71. What is the vertex and minimum value of F(X)?

LekaFEV [45]

The veretx is normally the minimum value
hack:
for f(x)=ax²+bx+c
the x value of the vertex is -b/2a
so
f(x)=1x²-16x+71
x value is -(-16)/(2*1)=16/2=8
find f(8) to find y value of vertex

f(8)=8²-16(8)+71
f(8)=64-128+71
f(8)=7

the vertex is (8,7)
the minimum value is 7

7 0

3 years ago

Easy Area problem <br><br> Need it fast

Gekata [30.6K]

Answer:

just subtract the area of the rectangle from the area of the carpet

fine I'll do it

Area of a rectangle= lb

Area of a square= a^2

Area of the remaining area= lb - a^2

= (12*4) - (2*2)

= 48-4

= 44 ft^2

5 0

3 years ago

HELP!!!!!!!!!!!

erica [24]

Your answer would be (b.) because -2+-3=-5

3 0

3 years ago

Read 2 more answers

The number of people arriving for treatment at an emergency room can be modeled by a Poisson process with a rate parameter of si

OverLord2011 [107]

Answer:

a) P(x=3)=0.089

b) P(x≥3)=0.938

c) 1.5 arrivals

Step-by-step explanation:

Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.

The variable X is modeled by a Poisson process with a rate parameter of λ=6.

The probability of exactly k arrivals in a particular hour can be written as:

$P(x=k)=\lambda^{k} \cdot e^{-\lambda}/k!\\\\P(x=k)=6^k\cdot e^{-6}/k!$

a) The probability that exactly 3 arrivals occur during a particular hour is:

$P(x=3)=6^{3} \cdot e^{-6}/3!=216*0.0025/6=0.089\\\\$

b) The probability that <em>at least</em> 3 people arrive during a particular hour is:

$P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938$

c) In this case, t=0.25, so we recalculate the parameter as:

$\lambda =r\cdot t=6\;h^{-1}\cdot 0.25 h=1.5$

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

$E(x)=\lambda=1.5$

3 0

3 years ago