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Maksim231197 [3]
3 years ago
5

In the equation shown below what is the "a"value? y= 2x2square +4x -9

Mathematics
1 answer:
Marat540 [252]3 years ago
6 0

Answer:

The "a" value is 2x^2

Step-by-step explanation:

This is because it is the first part of the equation. The parts of the equation are given the values a, b, and c based on their position in the equation.

If this answer is correct, please make me Brainliest!

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Maria is 8 years older than her brother, and the sum of their ages is 72 years. How old is her brother?
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Answer:

32

Step-by-step explanation:

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Answer true or false for 1-10 (picture above)
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7)\ \sqrt{100+64}=\sqrt{100}+\sqrt{64}\qquad FALSE\\\\8)\ \sqrt{30}=\sqrt{5\cdot6}=\sqrt5\cdot\sqrt6\qquad TRUE\\\\9)\ \sqrt{44}=\sqrt{22+22}=\sqrt{22}+\sqrt{22}\qquad FALSE\\\\10)\ \sqrt{10\cdot10}=\sqrt{10}\cdot\sqrt{10}\qquad TRUE

3 0
3 years ago
Two poles are connected by a wire that is also connected to the ground. The first pole is 18 ft tall and the second pole is 24 f
9966 [12]

Answer:

  72 feet from the shorter pole

Step-by-step explanation:

The anchor point that minimizes the total wire length is one that divides the distance between the poles in the same proportion as the pole heights. That is, the two created triangles will be similar.

The shorter pole height as a fraction of the total pole height is ...

  18/(18+24) = 3/7

so the anchor distance from the shorter pole as a fraction of the total distance between poles will be the same:

  d/168 = 3/7

  d = 168·(3/7) = 72

The wire should be anchored 72 feet from the 18 ft pole.

_____

<em>Comment on the problem</em>

This is equivalent to asking, "where do I place a mirror on the ground so I can see the top of the other pole by looking in the mirror from the top of one pole?" Such a question is answered by reflecting one pole across the plane of the ground and drawing a straight line from its image location to the top of the other pole. Where the line intersects the plane of the ground is where the mirror (or anchor point) should be placed. The "similar triangle" description above is essentially the same approach.

__

Alternatively, you can write an equation for the length (L) of the wire as a function of the location of the anchor point:

  L = √(18²+x²) + √(24² +(168-x)²)

and then differentiate with respect to x and find the value that makes the derivative zero. That seems much more complicated and error-prone, but it gives the same answer.

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2 years ago
Find three ratios that are equivalent to 20:25
V125BC [204]

Answer:

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Step-by-step explanation:

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The directrix of a parabola is x = 4. Its focus is (2,6) .
Sati [7]

Answer:

Step-by-step explanation:

If you plot the directrix and the focus, you can see that the focus is to the left of the directrix.  Since a parabola ALWAYS wraps itself around the focus, our parabola opens sideways, to the left to be specific.  The formula for the parabola that opens to the left is

-(y-k)^2=4p(x-h)

We will solve this for x at the end.  The negative is out front because it opens to the left.  If it opened to the right, it would be positive.

The vertex of a parabola is exactly halfway between the focus and the directrix, so our vertex coordinates h and k are (3, 6). P is defined as the distance between the vertex and the directrix, or the vertex and the focus.  Since the vertex is directly between both the directrix and the focus, each distance is the same.  P = 1.  Filling in what we have now:

-(y-6)^2=4(1)(x-3) which simplifies to

-(y-6)^2=4(x-3)

Now we will solve it for x.

-(y-6)^2=4x-12 and

-(y-6)^2+12=4x so

-\frac{1}{4}(y-6)^2+12=x

4 0
3 years ago
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