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lutik1710 [3]
3 years ago
13

Try to fill in the missing numbers using 1,2,3,4,5,6,7,8,9 only once each?

Mathematics
1 answer:
alexandr402 [8]3 years ago
5 0
Nine plus one ten
nine plus two eleven
nine plus three twelve
nine plus four thirteen
nine plus five fourteen
nine plus six fifteen
and so on... until eighteen
Then use multiplication with different combinations of the numbers.
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A circle has been split into 8 sectors each of which can be colored as 4 different colors, and no consecutive sectors are colore
Eva8 [605]

Answer:

5832 ways

Step-by-step explanation:

Since the circle has 8 sectors and there is 4 colour,

Assuming the sectors are numbered 1 to 8,

Sector 1 : can be coloured with any of the 4 colour in 4 ways

Sector 2 can be coloured with any of the remaining 3 colours in 3 ways

Sector 3 in 3 ways without using the colour in sector 2

Sector 4 in 3 ways without using the colour in sector 3

Sector 5 in 3 ways without using the colour in sector 4

Sector 6 in 3 ways without using the colour in sector 5

Sector 7 in 3 ways without using the colour in sector 6

Sector 8 in 2 ways without using the colours in sector 1 and 7

Number of ways of colouring = 4*3*3*3*3*3*3*2 = 5832 ways

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3 years ago
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Goshia [24]

Answer:

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