Answer:
Name: Zinc
Symbol: Zn
Atomic Number: 30
Atomic Mass: 65.39 amu
Melting Point: 419.58 °C (692.73 K, 787.24396 °F)
Boiling Point: 907.0 °C (1180.15 K, 1664.6 °F)
Number of Protons/Electrons: 30
Number of Neutrons: 35
Classification: Transition metal
Crystal Structure: Hexagonal
Density at 293 K: 7.133 g/cm3
Color: bluish
('lil long, sorry)
Answer:
Acceleration of the ship, 
Explanation:
It is given that,
Mass of both ships, 
Distance between two ships, d = 110 m
The gravitational force between two ships is given by :


F = 8.38 N
Let a is the acceleration. Now, using second law of motion as :



So, the acceleration of either ship due to the gravitational attraction of the other is
. Hence, this is the required solution.
Sound waves....................................