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spayn [35]
3 years ago
9

The emission of x rays can be described as an inverse photoelectric effect.

Physics
1 answer:
timama [110]3 years ago
4 0

Answer:

The potential difference through which an electron accelerates to produce x rays is 1.24\times 10^4\ volts.                                                  

Explanation:

It is given that,

Wavelength of the x -rays, \lambda=0.1\ nm=0.1\times 10^{-9}\ m

The energy of the x- rays is given by :

E=\dfrac{hc}{\lambda}

The energy of an electron in terms of potential difference is given by :

E=eV

So,

\dfrac{hc}{\lambda}=eV

V is the potential difference

e is the charge on electron

V=\dfrac{hc}{e\lambda}

V=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-19}\times 0.1\times 10^{-9}}

V = 12431.25 volts

or

V=1.24\times 10^4\ volts

So, the potential difference through which an electron accelerates to produce x rays is 1.24\times 10^4\ volts. hence, this is the required solution.

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Vfy=?

  h = 10 m

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7 0
3 years ago
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The gravitational force experienced by Earth due to the Moon is ________ the gravitational force experienced by the Moon due to
Vsevolod [243]

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5 0
3 years ago
This is a question on my physics test :)
Licemer1 [7]

Answer:

119.6 J/Kg°C

Explanation:

Data obtained from the question include:

Mass of substance (ms) = 170 g

Initial temperature of substance (Ts) = 120 °C

Volume of water = 200 mL

Initial temperature of water (Ts) = 10 °C

Temperature of the mixture (T2) = 12.6 °C

Density of water = 1 g/mL

Specific heat capacity of water (Cw) = 4200J/Kg°C

Specific heat capacity of substance (Cs) =..?

Next, we shall determine the mass of water. This can be obtained as follow:

Volume of water = 200 mL

Density of water = 1 g/mL

Mass of water =..?

Density = mass /volume

1 = mass /200

Cross multiply

Mass of water = 1 x 200

Mass of water = 200 g

Convert 200 g of water to Kg

Mass of water = 200/1000 0.2 Kg

Mass of water = 0.2 Kg

Now, we obtained the specific heat capacity of the substance using the following formula:

MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

Mass of water = 0.2 Kg

Initial temperature of water (Ts) = 10 °C

Specific heat capacity of water (Cw) = 4200J/Kg°C

Temperature of the mixture (T2) = 12.6 °C

Mass of substance (ms) = 170 g = 170/1000 = 0.17 Kg

Initial temperature of substance (Ts) = 120 °C

Specific heat capacity of substance (Cs) =..?

MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

0.2× 4200(12.6 – 10) + 0.17×Cs×(12.6 – 120) = 0

840(2.6) + 0.17Cs(– 107.4) = 0

2184 – 18.258Cs = 0

Rearrange

2184 = 18.258Cs

Divide both side by the coefficient of Cs i.e 18258

Cs = 2184/18.258

Cs = 119.6 J/Kg°C

Therefore, the specific heat capacity of the substance is 119.6 J/Kg°C

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