1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
spayn [35]
3 years ago
9

The emission of x rays can be described as an inverse photoelectric effect.

Physics
1 answer:
timama [110]3 years ago
4 0

Answer:

The potential difference through which an electron accelerates to produce x rays is 1.24\times 10^4\ volts.                                                  

Explanation:

It is given that,

Wavelength of the x -rays, \lambda=0.1\ nm=0.1\times 10^{-9}\ m

The energy of the x- rays is given by :

E=\dfrac{hc}{\lambda}

The energy of an electron in terms of potential difference is given by :

E=eV

So,

\dfrac{hc}{\lambda}=eV

V is the potential difference

e is the charge on electron

V=\dfrac{hc}{e\lambda}

V=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-19}\times 0.1\times 10^{-9}}

V = 12431.25 volts

or

V=1.24\times 10^4\ volts

So, the potential difference through which an electron accelerates to produce x rays is 1.24\times 10^4\ volts. hence, this is the required solution.

You might be interested in
Two cars are traveling along a straight line in the same direction, the lead car at 25 m/s and the other car at 35 m/s. At the m
Phoenix [80]

Answer:

a. t_1=12.5\ s

b. a_2=-13.61\ m.s^{-2}  must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

c. t_2=2.5714\ s is the time taken to stop after braking

Explanation:

Given:

  • speed of leading car, u_1=25\ m.s^{-1}
  • speed of lagging car, u_{2}=35\ m.s^{-1}
  • distance between the cars, \Delta s=45\ m
  • deceleration of the leading car after braking, a_1=-2\ m.s^{-2}

a.

Time taken by the car to stop:

v_1=u_1+a_1.t_1

where:

v_1=0 , final velocity after braking

t_1= time taken

0=25-2\times t_1

t_1=12.5\ s

b.

using the eq. of motion for the given condition:

v_2^2=u_2^2+2.a_2.\Delta s

where:

v_2= final velocity of the chasing car after braking = 0

a_2= acceleration of the chasing car after braking

0^2=35^2+2\times a_2\times 45

a_2=-13.61\ m.s^{-2} must be the minimum magnitude of deceleration to avoid hitting the leading car before stopping

c.

time taken by the chasing car to stop:

v_2=u_2+a_2.t_2

0=35-13.61\times t_2

t_2=2.5714\ s  is the time taken to stop after braking

7 0
3 years ago
Line segment gj is a diameter of circle l. angle k measures (4x 6)°. circle l is inscribed with triangle g j k. line segment g j
choli [55]

The value of x in the given right triangle in a semicircle is determined as 21.

<h3>What is the measure of a triangle in a semicircle?</h3>

The triangle in a semicircle is always a right angle triangle.

From the figure shown, we can say that the triangle  G J K is right triangle and m<K = 90degrees.

Given that m<K = 4x + 6, we will can use the following equation to find the value of x as shown:

4x + 6 = 90

4x = 90 - 6

4x = 84

x = 21

Thus, the value of x in the given right triangle in a semicircle is determined as 21.

Learn more about right angle here: brainly.com/question/64787

#SPJ4

8 0
2 years ago
Some thermal containers have layers of materials to keep drinks cold for as long as possible. Which design would help keep ice f
grin007 [14]
The answer is D correct me if I’m wrong
5 0
3 years ago
Read 2 more answers
A cart is uniformly decelerating from rest. The net force acting on the cart is
mina [271]

Answer:

i think the answer is constant

7 0
3 years ago
A place kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. half the crowd hopes the ball will clear
trapecia [35]
<span>The ball clears by 11.79 meters Let's first determine the horizontal and vertical velocities of the ball. h = cos(50.0)*23.4 m/s = 0.642788 * 23.4 m/s = 15.04 m/s v = sin(50.0)*23.4 m/s = 0.766044 * 23.4 m/s = 17.93 m/s Now determine how many seconds it will take for the ball to get to the goal. t = 36.0 m / 15.04 m/s = 2.394 s The height the ball will be at time T is h = vT - 1/2 A T^2 where h = height of ball v = initial vertical velocity T = time A = acceleration due to gravity So plugging into the formula the known values h = vT - 1/2 A T^2 h = 17.93 m/s * 2.394 s - 1/2 9.8 m/s^2 (2.394 s)^2 h = 42.92 m - 4.9 m/s^2 * 5.731 s^2 h = 42.92 m - 28.0819 m h = 14.84 m Since 14.84 m is well above the crossbar's height of 3.05 m, the ball clears. It clears by 14.84 - 3.05 = 11.79 m</span>
4 0
4 years ago
Other questions:
  • Mercury was named after the roman god of speed why is it an appropriate name for the planet
    6·1 answer
  • Two identical point charges of +Q coul are separated by a distance of 10 cm.
    11·1 answer
  • Using the work energy theorem. What is the velocity of a 850kg car after starting at rest when 13,000J of work is done to it.
    12·1 answer
  • Would you expect the bonds in ammonia to be polar covalent?
    14·1 answer
  • What happen to the light ray when it enters to crown glass block ?
    6·1 answer
  • What is scientific evidence and when do we have enough?
    9·1 answer
  • Which of the following are used in an electrochemical cell?
    11·1 answer
  • A motorcycle stunt driver zooms off the end of a cliff at a speed of 41.9 meters per second. If he lands after 1.62 seconds, wha
    5·1 answer
  • Light of wavelength 519 nm passes through two slits. In the interference pattern on a screen 4.6 m away, adjacent bright fringes
    9·1 answer
  • Please help/ show work !!! Also don’t answer by putting a link!!
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!