Question

Light of wavelength 519 nm passes through two slits. In the interference pattern on a screen 4.6 m away, adjacent bright fringes are separated by 4.0 mm. What is the separation of the two slits

Answer 1

Answer:

The appropriate solution is "0.597 mm".

Explanation:

Given that:

Wavelength,

$\lambda = 519 \ nm$

or,

  $=519\times 10^{-9}$

Distance,

$D=4.6 \ m$

Separated by,

$\beta = 4.0 \ mm$

or,

   $=4.0\times 10^{-3}$

As we know,

⇒ $\beta=\frac{\lambda D}{d}$

or,

The separation of two slits will be:

⇒ $d=\frac{\lambda D}{\beta}$

By putting the values, we get

       $=\frac{(519\times 10^{-9})(4.6)}{4.0\times 10^{-3}}$

       $=5.97\times 10^{-4}$

or,

       $=0.597 \ mm$