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3 years ago

5

A motorcycle stunt driver zooms off the end of a cliff at a speed of 41.9 meters per second. If he lands after 1.62 seconds, wha

t is the height of the cliff?

1 answer:

tiny-mole [99]3 years ago

8 0

Of the cliff?

Projectile motion
In the problem we are asked to find a height of certain cliff when a motorcycle stunt driver zoom out horizontally at the end the cliff at an initial velocity. So we will use one of the kinematics equation for projectile motion,

y
=
v
o
y
t
+
1
2
g
t

where
v
o
y
is just equal to zero since we can assume that the driver zooms out horizontally,
g
=
9.8

m
/
s
2
and
t
is time after

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Answer to the question is:

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An aluminum calorimeter with a mass of 100 g contains 250 g of water. The calorimeter and water are in thermal equilibrium at 10

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Answer:

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We have,

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$Q_{out}=m_c.c_c.(T_c-T_f)+m.c.(T-T_f)$

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$c=$ specific heat of the unknown material

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♨Rage♨

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3 years ago