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Snezhnost [94]
3 years ago
5

The ratio of the inductive reactance to the

Physics
1 answer:
BARSIC [14]3 years ago
6 0

Answer:

<em>The non resonance frequency of the generator is = 1201.79 Hz</em>

Explanation:

At resonance,

f₀ = 1/2π√LC..................... Equation 1

Where f₀ = resonance frequency, L = inductance, C = capacitance

making LC the subject of the equation

LC = 1/4πf₀²..................... Equation 2

<em>Given: </em>f₀ = 225 Hz, and π = 3.143

<em>Substituting these values into equation 2,</em>

LC = 1/(4×3.143²×225²)

LC = 1/2000385.9

LC = 5×10⁻⁷

If the ratio of capacitive reactance to inductive reactance = 5.36

1/2πfC/2πfL = 5.36

1/4π²f²LC = 5.36

Where f = frequency of the non resonant

making f the subject of the equation

f = 5.36/2π√LC ............. Equation 3

Substituting the value of LC = 5×10⁻⁷ into equation 3

f = 5.36/2×3.143√(5×10⁻⁷)

f = 5.36/(6.286×0.00071)

f = 5.36/0.00446

<em>f = 1201.79 Hz</em>

<em>Thus the non resonant frequency of the generator is = 1201.79 Hz</em>

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Explanation:

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P(t) = (9.20*cos(69°)*t, -4.9m/s^2*t^2 + 9.20m/s^2*sin(69°)*t)

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t = (4.22/ 9.20*cos(69°)) = 1.28s

Now we evaluate the y-position in this time:

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3 years ago
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Answer:

1. 2.5×10¯⁹ N

2. 3.33×10¯¹¹ m/s²

Explanation:

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The force of attraction between the astronaut and his spacecraft can be obtained as follow:

F = GM₁M₂ /r²

F = 6.67×10¯¹¹ × 75 × 125000 / 500²

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Acceleration (a) of astronaut =?

The acceleration of the astronaut can be obtained as follow:

F = ma

2.5×10¯⁹ N = 75 × a

Divide both side by 75

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a = 3.33×10¯¹¹ m/s²

Thus, the acceleration the astronaut is 3.33×10¯¹¹ m/s²

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