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4 years ago

Q. Two balls are released simultaneously from a certain

Physics

1 answer:

Mice21 [21]4 years ago

5 0

Answer:Yes

Explanation:

Time taken for the first ball will depend upon the height of roof. As it is dropped so initial vertical velocity will be zero.

so time taken will be

$t=\sqrt{\frac{2h}{g}}$

where h=height of roof

g=acceleration due to gravity

Horizontal velocity is given to second ball so it cover more horizontal distance as compared to first but time taken will be same as it has to cover same vertical distance with zero vertical velocity and time taken depends on height of roof and g.

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The Indianapolis Motor Speedway has four banked curves, each of which forms a quarter of a circle. Suppose a race car speeds alo

boyakko [2]

Answer:

r = 255.68 m

Explanation:

When a body moves in a circular path, an acceleration, due to constant change in its direction, is developed, known as centripetal acceleration. The centripetal acceleration acts towards the center of the circular path. The formula to calculate the centripetal acceleration is given as follows:

ac = v²/r

where,

ac = centripetal acceleration = 22 m/s²

v = tangential speed = 75 m/s

r = radius of curve = ?

Therefore,

22 m/s² = (75 m/s)²/r

r = (75 m/s)²/(22 m/s²)

4 0

3 years ago

At a certain moment, a car travelling at 40mph begins braking for a railroad crossing. Assume thatthe acceleration is constant (

egoroff_w [7]

Answer:

Part a)

$v_f = 17.88 - (0.15) t$

Part b)

$d = 1072.8 m$

Explanation:

As we know that initial speed of the car is

$v = 40 mph$

$v = 40 \times (\frac{1609}{3600})$

$v = 17.88 m/s$

now we have

$v_f = v_i + at$

$0 = 17.88 + a(120)$

$a = -0.15 m/s^2$

Part a)

As we know that acceleration is constant here

so we have

$v_f = v_i + at$

$v_f = 17.88 - (0.15) t$

Part b)

distance moved by the car is given as

$d = \frac{v_F + v_i}{2} t$

now we have

$d = \frac{0 + 17.88}{2}(120)$

$d = 1072.8 m$

3 0

3 years ago

Which properties do metalloids share with metals?

Inga [223]

Metals are not brittle so it can’t be the first one or the third one, both metalloids and metals are shiny so it can’t be the second one. Therefore, it would be the last one because both metalloids and metals are shiny and both are solids at room temperature because it is not a high enough melting point.

ANSWER: Both are shiny and are solid at room temperature.

4 0

3 years ago

Read 2 more answers

Magnetic fields and electric fields are identical in what

forsale [732]

Magnetic fields and electric fields are similar on the basis of the forces and its application.

<h3>What is an electric field?</h3>

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

Magnetic and electric fields have certain similarities, are as follows;

1. Both the electric force and magnetic forces are the non-contact forces.

2. Both acts between the two entity having certain mass.

3. Both have their respective ranges.

Hence, magnetic fields and electric fields are similar on the basis of the forces and its application.

To learn more about the electric field, refer to the link;

brainly.com/question/26690770

#SPJ1

4 0

2 years ago

If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the cu

zubka84 [21]

Answer:

minimum speed is 15.35 m/s

frictional coefficient is 0.26

Explanation:

given data

radius = 84 m

angle = 16°

speed = 16 km/h = 4.43 m/s

to find out

minimum speed and minimum coefficient

solution

we will apply here formula for velocity that is

velocity² = radius × g × tanθ

v² = 84 × 9.8 × tan16

v² = 236.04

v = 15.35 m/s

and

we find first friction force here

friction force 1 = m v² /r

friction force 1 = m (15.35)² / 84 = 2.80 m

and

friction force 2 = m v² /r

friction force 2 = m (4.43)² / 84 = 0.245 m

so total friction force = f1 - f2

total friction force = 2.80 - 0.245 = 2.55 m

so frictional coefficient = friction force /g

frictional coefficient = 2.55 / 9.8

so frictional coefficient is 0.26

4 0

3 years ago

Read 2 more answers