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Vladimir [108]
3 years ago
7

a local school has a gymnasium that is 48ft long, 36ft wide with an 18ft high ceiling. the school maintenance staff is painting

the four walls. each can of paint contains enough paint to cover 400 ft². how many cans of paint are needed to cover the gym?​
Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Answer:

8

Step-by-step explanation:

Let's first measure the four walls.  We'll have 2 walls 48 ft wide x 18 ft high (the longer walls), then 2 walls 36 ft x 18 ft high.

These are rectangles we can easily calculate the area:

longer walls: 2 (48 * 18) = 2 * 864 = 1,728 sq ft

shorter walls: 2 (36 x 18) = 2 * 648 = 1,296 sq ft

Total of the walls: 1,728 + 1,296  = 3,024 sq ft.

Now, we assume they'll paint everything and that there are no windows.

Each can covers 400 sq ft.

If we divide 3,024 by 400 we get 7.56

So, they'll need to buy 8 cans of paint to do the job.  In such problems, we always round up, otherwise they wouldn't have enough paint.

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QUICKLY PLEASE!!<br> 18POINTS!<br> 6(3p – 2) = 24
Gekata [30.6K]

Answer:

p= 2

Step-by-step explanation:

So first you want to distribute the 6 to 3p-2 which basically means multiply

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6 times 3p is 18 and 6 time -2 is -12

* remember a negative and a positive equal a negative*

18p-12=24

you want to get 18p by itself, so in order to do that you can add 12 to both sides because if you add 12 on the left side it cancels out -12 and whatever you do to one side you have to do it to the other so add 12 to 24 which is 36

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since you want to get p by itself you divide p on both sides so it can cancel out 18 and 36/18 is 2

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Answer:

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