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Vladimir [108]
3 years ago
7

a local school has a gymnasium that is 48ft long, 36ft wide with an 18ft high ceiling. the school maintenance staff is painting

the four walls. each can of paint contains enough paint to cover 400 ft². how many cans of paint are needed to cover the gym?​
Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Answer:

8

Step-by-step explanation:

Let's first measure the four walls.  We'll have 2 walls 48 ft wide x 18 ft high (the longer walls), then 2 walls 36 ft x 18 ft high.

These are rectangles we can easily calculate the area:

longer walls: 2 (48 * 18) = 2 * 864 = 1,728 sq ft

shorter walls: 2 (36 x 18) = 2 * 648 = 1,296 sq ft

Total of the walls: 1,728 + 1,296  = 3,024 sq ft.

Now, we assume they'll paint everything and that there are no windows.

Each can covers 400 sq ft.

If we divide 3,024 by 400 we get 7.56

So, they'll need to buy 8 cans of paint to do the job.  In such problems, we always round up, otherwise they wouldn't have enough paint.

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A two-digit number is written at random. The probability that the number will be odd is . The probability that the number will b
Makovka662 [10]
Step-by-step explanation:
GIVEN: Two digit number means we will have to choose from numbers 0-9 for the second digit and 1-9 for the first digit. (since zero can't be in the tens place)
Formula: We will use m x n. That is, m is the number of elements we can use for the first digit and n will be the number of elements we can use for the second digit.
Sample Space: To get the probability, we must find the sample space or all the outcomes.
m - 9 elements (1-9)
m - 9 elements (1-9)n - 10 elements (0-9)
m x n = 9x10 =90
90 is our sample space.
A. An odd number
Conditions: For an odd number, the second number will determine whether or not it is an odd number. For the first digit, we can use 1-9.
Elements:
m - 9 elements (1-9)
m - 9 elements (1-9)n - 5 elements (1,3,5,7,9)
m x n=9x5=45
SOLVE (probability)
Probability= possible outcomes/sample space
P=45/90
P=1/2
B. Larger than 75.
Conditions: The first digit could be equal to 7 or greater. But n will only be greater than 5 if and only if m=7 and n could be any number if m>7.
Elements 1:
m - 1 element (7)
m - 1 element (7)n - 4 elements (6,7,8,9)
m - 1 element (7)n - 4 elements (6,7,8,9)m x n=1x4=4
Elements 2:
m - 2 elements (8,9)
m - 2 elements (8,9)n - 10 elements (0,1,2,3,4,5,6,7,8,9,)
m - 2 elements (8,9)n - 10 elements (0,1,2,3,4,5,6,7,8,9,)mxn=2x10=20
TOTAL: 4+20=24
SOLVE (PROBABILITY)
Probability= possible outcomes/sample space
P=24/90
P=4/15
C. multiple of 5
Condition: the second digit must be either 0 or 5 and the first digit could be any digit.
Elements:
m - 9 elements (1-9)
m - 9 elements (1-9)n - 2 elements (0,5)
m x n =9x2=18
SOLVE (PROBABILITY)
P=18/90
P=1/5
D. An even number smaller than 40
Condition: The first digit could be equal to 4 but the second digit must be even (excluding zero). Another situation is the first digit would be greater than 4 and the second digit would be any even number.
Elements 1:
m - 1 element (4)
n - 4 elements (2,4,6,8)
m x n = 1x4=4
Elements 2:
m - 5 elements (5,6,7,8,9)
n - 5 elements (0,2,4,6,8)
mxn=5x5=25
TOTAL: 25+4=29
SOLVE: Probability
P=29/90
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Answer:

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Answer:

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Step-by-step explanation:

3x-5=19\\

The first step is to add -5 to both sides:

(3x-5)+5=19+5\\3x=24

The next step is to divide 3 on both sides:

\frac{3x}{3} =\frac{24}{3}

x=8

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